Volume is found by length multiplied by width multiplied by height. Therefore our first equation is 2 multiplied by 5 and 1/3 or 16/5 as a mixed number multiplied by 10 3/4 or 43/10 as a mixed number. This will give us the total volume. As there are 8 servings, we will need to divide by 8 or multiply by 1/8 to find the volume of each serving. The final answer is 86/25 which simplified to 3 and 11/25

5 0

3 years ago

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A math teacher was frustrated at the number of students leaving their graphing calculator behind in her classroom at the end of

AleksAgata [21]

Answer:

The 99% confidence interval for the proportion of all students at this school who have their names written on their graphing calculators is (0.4652, 0.8148).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

A random sample of 50 students is selected, and of the students questioned, 32 had their names written on their graphing calculators.

This means that $n = 50, \pi = \frac{32}{50} = 0.64$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.64 - 2.575\sqrt{\frac{0.64*0.36}{50}} = 0.4652$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.64 + 2.575\sqrt{\frac{0.64*0.36}{50}} = 0.8148$

The 99% confidence interval for the proportion of all students at this school who have their names written on their graphing calculators is (0.4652, 0.8148).

8 0

3 years ago

PLEASE ANSWER THIS FAST Will the red square and the orange square always equal the blue square? What colored square is the hypot

Vikentia [17]

Step-by-step explanation:

The area of the blue square will always equal the sum of the area of the orange and red rectangles

The pythagorian theorem:

a²+b² = c²

now let a be the side of the red triangle and b the side of the orange one

so a² is the area of the red triangle and b² is the area of the orange one

Let c be the side of the blue rectangle

so c² is the area of it

then what we concluded is right

the hypotenuse is the blue side since it is the larger one

6 0

3 years ago