3 years ago

(7,0), endpoint (3,-4)

Mathematics

1 answer:

mafiozo [28]3 years ago

3 0

Answer:

11,4 is the answers for the question

Step-by-step explanation:

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just use what you know about this stuff

(a+36d)/(a+20d) = (a+55d)/(a+36d)

(a+36d)^2 = (a+55d)(a+20d)

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3ad = 196d^2

3a = 196d

That is, for any value of n,

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So, there is no unique solution.

If n=1, then a=196 and d=3. The terms are

196+20*3 = 256

196+36*3 = 304

196+55*3 = 361

304/256 = 361/304

You can easily verify that it works for any value of n.

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