Answer:
No we can consider A as single event. See the explanation below
Step-by-step explanation:
Let's define the event A as:
A=" Select a 4 from a standard deck of 52 cards"
We know that in a standard deck we have 4 different types of 4, spade, heart, diamond and club.
And by definition of simple event we need to have just one possible outcome in the experiment, and on this case we have 4 possible options for event A, so for this reason the event A can't be considered as simpl event.
Answer:
9
Step-by-step explanation:
3^5 = 243
3^3 = 27
243 / 27 = 9
Hope this helps :)
Answer:6
Step-by-step explanation:
Subtract the three 1 point shots
Subtract the four 3 point shots
You are left with 12, and you split that in 2 because they're 2 point shots.
For 1 play, the chance of gaining $8 is 4/38, while the chance of losing the $1 is 34/38. Therefore, the expected value is ($8)(4/38) + ($-1)(34/38) = $(-1/19). Over 50 plays, which are mutually independent of each other, we multiply the number of plays by the expected value to get $(-50/19) = $-2.63.
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W^2+5w-66=0
Factor
(w+11)(w-6)=0
w+11=0
w=-11 (not possible - cant have negative length
w-6=0
w=6
L(6)=66
L=11
Width = 6
Length = 11
