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3 years ago

Someone please help me with math.

Mathematics

1 answer:

umka2103 [35]3 years ago

5 0

All you have to do is graph both of the equations given and find the point of intersection. This point will be your solution.

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11. ¿Es mayor 1/4 que 0.50? Justifica tu pregunta

musickatia [10]

Eh yo creo que no, si estoy mal los siento

3 0

3 years ago

Prove the polynomial identity. (2x−1)2+2(2x−1)=(2x+1)(2x−1) Drag and drop the expressions to correctly complete the proof of the

Alex_Xolod [135]

Answer:

Step-by-step explanation:

Given expression is,

(2x - 1)² + 2(2x - 1) = (2x - 1)(2x + 1)

To prove this identity we will take the left hand side of the equation and will prove equal to the right side.

(2x - 1)² + 2(2x - 1) = (2x - 1)(2x + 1)

4x² - 4x + 1 + 4x - 2 = (2x - 1)(2x + 1)

4x² - 1 = (2x - 1)(2x + 1)

(2x - 1)(2x + 1) = (2x - 1)(2x + 1) [Since a² - b² = (a - b)(a + b)]

6 0

4 years ago

Find the dimensions of an American football field. The length is 200 ft more than the width, and the perimeter is 1,040 ft. Find

natka813 [3]

Answer:

The width of the football field is 160 feet.

The length of the football field is 360 feet.

Step-by-step explanation:

Let w represent width of the football field.

We have been given that the length is 200 ft more than the width, so the length of the field would be $w+200$ .

We are also told that the perimeter is 1,040 ft. We know that football field is in form of rectangle, so perimeter of field would be 1 times the sum of length and width. We can represent this information in an equation as:

$2(w+w+200)=1040$

Let us solve for w.

$2(2w+200)=1040$

$4w+400=1040$

$4w+400-400=1040-400$

$4w=640$

$\frac{4w}{4}=\frac{640}{4}$

$w=160$

Therefore, the width of the football field is 160 feet.

Upon substituting $w=160$ in expression $w+200$ , we will get length of field as:

$w+200\Rightarrow 160+200=360$

Therefore, the length of the football field is 360 feet.

7 0

3 years ago

Solve by graphing.

melisa1 [442]

Given:

The given system of equations is:

$2x+y=1$

$x-2y=8$

To find:

The solution to this system of equations by graphing.

Solution:

We have,

$2x+y=1$

$x-2y=8$

The table of values for first equation is:

x y

0 1

1 -1

Plot the points (0,1) and (1,-1) on a coordinate plane and connect them a straight line.

The table of values for second equation is:

x y

0 -4

2 -3

Plot the points (0,-4) and (2,-3) on a coordinate plane and connect them a straight line.

The graphs of given equations are shown in the below figure.

From the below figure, it is clear that the lines intersect each other at point (2,-3). So, the solution of the given system of equations is (2,-3).

Therefore, the solution to this system of equations is:

x-coordinate: 2

y-coordinate: -3

7 0

3 years ago

What are the missing sides and angles of this triangle? What is the area?

Butoxors [25]

This does not appear to be a right triangle. However, we know 2 sides and the included angle, so can find the unknown side length. Let x represent this length. Then:

x^2 = (9 m)^2 + (12 m)^2 - 2(9m)(12 m)*cos 30 degrees, or

x^2 = 81 + 144 - 216(sqrt(3) / 2). Please solve for x^2 and then solve the result for x, making sure to choose the positive value. The result will be the length of the side opposite the 30 degree angle.

With 1 of 3 angles known, and 3 of 3 sides known, you can use the Law of Sines to find the other two angles. As a reminder, the Law of Sines looks like this:

a b c
-------- = --------- = ----------
sin A sin B sin C.

You can give the 30-deg angle any name you want; then a, the length of the side opposite the 30-deg angle, which you have just found. And so on.

4 0

3 years ago