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3 years ago

What expression is equivalent to 2^-3/2^-5?

Mathematics

1 answer:

mr_godi [17]3 years ago

6 0

2^2 , or 4
since the exponents have the same base, we can subtract the exponent of the numerator by the exponent in the denominator.

So 2^-3 - 2^-5 = 2^(-3-(-5)) = 2^2

The new exponent is 2 because -3-(-5) is equal to 2.

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If a store advertised a sale that gave customers a 1/4 discount what is the fractional part of the original price that the custo

mina [271]

It will be 3/4 of the original price

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3 years ago

If EG=19 and FG=12 then EF=?

Volgvan

Answer:

EF = 31

Step-by-step explanation:

Note that in both line segments (EG & FG), they both have point G in them. This means that point G is the shared point and the mid-point. Add the two line segments together to get the full segment.

EG + FG = EF

19 + 12 = 31

31 is your answer

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3 years ago

When Klorina swims with the current, she swims 10 km in 2 h. Against the current, she can swim only 8 km in the same time. How f

nasty-shy [4]

Answer:

Klorina's rate in still water is 4.5 km/h

Current's rate is 0.5 km/h

Step-by-step explanation:

Let

x km/h = Klorina's rate in still water

y km/h = current's rate

<u>With the current (current helps):</u>

Distance = 10 km

Time = 2 hours

Rate = x + y km/h

$10=2(x+y)$

<u>Against the current:</u>

Distance = 8 km

Time = 2 hours

Rate = x - y km/h

$8=2(x-y)$

Divide both equations by 2:

$x+y=5\\ \\x-y=4$

Add these equations:

$x+y+x-y=5+4\\ \\2x=9\\ \\x=4.5\ km/h$

Subtract these two equations:

$(x+y)-(x-y)=5-4\\ \\x+y-x+y=1\\ \\2y=1\\ \\y=0.5\ km/h$

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3 years ago

Find the % of change. Original price: $185 New price: $160

mojhsa [17]

Answer:

-13.51

Step-by-step explanation:

work out the difference (increase) between the two numbers you are comparing. Then: divide the increase by the original number and multiply the answer by 100. % increase = Increase ÷ Original Number × 100.,

so, -13.51

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2 years ago

A 50-foot flagpole is at the entrance of a building that is 300 feet tall. If the length of the flagpole's shadow is 30 feet at

Soloha48 [4]

The equation you can use to solve the problem is;

50/30 = 300/x

Next Cross Multiply

50x = 9000

x = 9000/50

x = 180

The building's shadow is 180 feet tall

7 0

3 years ago

What expression is equivalent to 2^-3/2^-5?​

What expression is equivalent to 2^-3/2^-5?