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3 years ago

Help me plzzzzzz........

Mathematics

2 answers:

adell [148]3 years ago

6 0

48 inches is the volume

katrin [286]3 years ago

5 0

Hi! I hope this helps!
You need to do 12in * 8in * 5in
Then you need to do 2in * 8in * 8in
Then you subtract 2in * 8in * 8in from 12in * 8in * 5in.
Then you should get your answer!

The answer should be 352in

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QUESTION 6 / 10

Nadya [2.5K]

Answer:

b. The stipend you receive.

Step-by-step explanation:

It would say paid intern if they were paid.

7 0

3 years ago

952.008 - ? = 300.50 Please help! I will give Brainlest!

SCORPION-xisa [38]

1252.508

952.008+300.5

3 0

3 years ago

Read 2 more answers

the length of a rectangle is 39cm less than five times its width. find the dimensions if the perimeter is 414cm. 2L+2W = P

Oksanka [162]

Answer:

41 cm and 166 cm

Step-by-step explanation:

As per question we have:

2(l + w) = 414 ⇒ l + w = 207
l = 5w - 39

Solve it for l by substitution:

5w - 39 + w = 207
6w = 207 + 39
6w = 246
w = 246/6
w = 41

Find l:

l = 207 - 41 = 166

4 0

3 years ago

Tan 3A in terms of tan

Zanzabum

Here's the sum rule for the tangent function:

$\tan(a+b)=\dfrac{\tan(a)+\tan(b)}{1-\tan(a)\tan(b)}$

In the special case a=b, this becomes the double angle formula:

$\tan(a+a)=\tan(2a)=\dfrac{\tan(a)+\tan(a)}{1-\tan(a)\tan(a)}=\dfrac{2\tan(a)}{1-\tan^2(a)}$

In your case, you case use the sum rule once:

$\tan(3a)=\tan(2a+a)=\dfrac{\tan(2a)+\tan(a)}{1-\tan(2a)\tan(a)}$

And use it again, in the special case of the double angle:

$\dfrac{\dfrac{2\tan(a)}{1-\tan^2(a)}+\tan(a)}{1-\dfrac{2\tan(a)}{1-\tan^2(a)}\tan(a)}$

We can obvisouly simplify this expression a lot: let's deal with the numerator and denominator separately: the numerator is

$\dfrac{2\tan(a)}{1-\tan^2(a)}+\tan(a) = \dfrac{2\tan(a)+\tan(a)-\tan^3(a)}{1-\tan^2(a)}$

and the denominator is

$1-\dfrac{2\tan(a)}{1-\tan^2(a)}\tan(a) = \dfrac{1-\tan^2(a)-2\tan^2(a)}{1-\tan^2(a)} = \dfrac{1-3\tan^2(a)}{1-\tan^2(a)}$

So, the fraction is

$\dfrac{2\tan(a)+\tan(a)-\tan^3(a)}{1-\tan^2(a)}\cdot \dfrac{1-\tan^2(a)}{1-3\tan^2(a)} = \dfrac{2\tan(a)+\tan(a)-\tan^3(a)}{1-3\tan^2(a)}$

8 0

4 years ago

What is the average rate of change from x=1 to x=3

olga2289 [7]

The average rate of change is calculated as the slope of the line between the two points on the graph. Since at x = 1, y = -3, and at x = 3, y = 1, these are the two points which we calculate the slope from. Using the formula
m = (y2 - y1)/(x2 - x1)
m = (1 - (-3))/(3 - 1)
m = 4/2
m = 2
Therefore the slope, or the average rate of change, between these points is 2.

4 0

3 years ago