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2 years ago

The sum of the first 6 terms of a geometric series is

Mathematics

1 answer:

jekas [21]2 years ago

7 0

Answer:

Step-by-step explanation:

The sum to n terms of a geometric sequence is

$S_{n}$ = $\frac{a(r^n-1)}{r-1}$

where a is the first term and r the common ratio

Here r = 5 and a has to be found, thus

$S_{6}$ = $\frac{a(5^6-1)}{5-1}$ , so

$\frac{a(15625-1)}{4}$ = 15624

Multiply both sides by 4

15624a = 62496 ( divide both sides by 15624

a = 4

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Miles brought the Russian novel Anna Kerenina. His paperback edition contains 992 page. Miles takes 3 days to read the first 50

Nesterboy [21]

Answer:

59.52 days

Step-by-step explanation:

So this is a simple problem we can solve easily

If it takes 3 days to read 50 pages then obviously his rate of reading is 50 pages per day

If we divide 992 by 50, then we can find how many 3 day increments it will take him

(992/50 is 19.84)

Now is we multiply 19.84 by 3, we get the total amount of days which is 59.52

I hope I helped and have a wonderful day!

7 0

2 years ago

What is 2p times p?<br> plz help

natulia [17]

2p*p= 2p^2 because when you multiply p by p it squares it, then you keep the 2 in front of it

4 0

2 years ago

The table shows the number of field goals made and field goals attempted by four different football kickers,

GrogVix [38]

Dan:12/16=3/4=75%
Josh:15/25=3/5=60%
Ryan:14/20=7/10=70%
Scott:10/15=2/3=67%
Answer:Dan

8 0

2 years ago

What is thirty seven squared?

SSSSS [86.1K]

Ur answer is 1369 that is ur answer hope it helped and hope u pass

4 0

3 years ago

Read 2 more answers

When fishing off the shores of Florida, a spotted seatrout must be between 10 and 30 inches long before it can be kept; otherwis

Mademuasel [1]

Answer:

There is a 97.585% probability that a fisherman catches a spotted seatrout within the legal limits.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

The lengths of the spotted seatrout that are caught, are normally distributed with a mean of 22 inches, and a standard deviation of 4 inches, so $\mu = 22, \sigma = 4$ .