.1x+.2y=-1
.5x-.9y=6.4
×-5 equation .1x+.2y=-1
-.5x-y=5
.5x-.9y=6.4
solve by elimination
-1.9y=11.4
÷-1.9 both sides
y=-6
solve for X
.1x+.2 (-6)=-1
.1x-1.2=-1
+1.2 both sides
.1x=.2
÷ 1 both sides
x=2
plug into 2nd equation to see if it's true
x=2
y=-6
0.5(2)-0.9(-6)=6.4
1+5.4=6.4
6.4=6.4 answers hold true
Answer:
P = 1/216
the probability that you would roll 3 sixes is 1/216
Step-by-step explanation:
For a given dice, there are six possibilities.
We have;
1,2,3,4,5,6
The probability of rolling a six(6) is;
P(6) = 1/6
Then, the probability of rolling 3 sixes is a multiple of the P(6), given as;
P = P(6) × P(6) × P(6)
P = 1/6 × 1/6 × 1/6
P = 1/216
the probability that you would roll 3 sixes is 1/216
Answer:
C
Step-by-step explanation:
If it is not C it is D, but i am pretty sure its c
Answer:
Step-by-step explanation:
The total number of lines, n(U) = 18
Let the number of lins with verb be n(V) = 11
Let the number of lines with adjectives be n(A) = 13
n(V n A) = 8
Find the number of lines that have a verb but no adjective, that is, n(V n A')
Mathematically, according to sets theory,
n(V) = n(V n A) + n(V n A')
So,
n(V n A') = n(V) - n(V n A) = 11 - 8 = 3.
Hence, only 3 lines have a verb but no adjectives.
Answer:
Need more information
Step-by-step explanation:
To answer your question, I need to know what equation you're looking at. If you could update your post with a picture or graph that'd be great.