Question

Three brothers have some money. The oldest has 3/5 of the total, and the youngest has 1/10 of the total. If the oldest brother has $108, how much do each of the other brothers have?

Answer 1

First, let's get rid of the unneeded info.

Oldest brother has $108 (3/5 the total)
Youngest brother has $x (1/10 the total)

Next let's find out the total. We do this by multiplying the oldest brothers money by 5/3 (the reciprocal).

108 × (5/3) = 180.

So the total amount of money is $180.

Finally, do 180 × (1/10) to find the youngest brother's amount.

180 × (1/10) = 18.

The youngest brother has $18.

Answer 2

Answer:

The youngest brother has ----> $\ 18$

The third brother has -------->  $\ 54$

Step-by-step explanation:

Let

x-----> the total money

we know that

The oldest brother has ----> $\frac{3}{5}x$ -----> $\frac{6}{10}x$

The youngest brother has ----> $\frac{1}{10}x$

The third brother has ----> $1-(\frac{6}{10}x+\frac{1}{10}x)=\frac{3}{10}x$

$\frac{3}{5}x=108$ ----> given problem

Solve for x

$x=108*5/3=\ 180$

so

The youngest brother has ----> $\frac{1}{10}(180)=\ 18$

The third brother has -------->  $\frac{3}{10}(180)=\ 54$