3 years ago

FACTOR COMPLETELY: x^2n+10x^n+16

Mathematics

1 answer:

Archy [21]3 years ago

8 0

Step-by-step explanation:

x^2n + 10x^n + 16

= (x^n)(x^n) + 10(x^n) + 16

= (x^n + 2)(x^n + 8).

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Rzqust [24]

Answer:

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Step-by-step explanation:

Simplify $(\frac{3}{-7} - \frac{11}{21} )$

$=> \frac{(-3 \times 3) - 11}{21}$

$=> \frac{-9 - 11}{21}$

$=> \frac{-20}{21}$

Find the additive inverse of $\frac{-20}{21}$ by using its property - <em>"Sum of a number & its additive inverse is always zero". </em>Assume that 'x' is an additive inverse of $\frac{-20}{21}$ .

$=> x + \frac{-20}{21} = 0$

$=> x = 0 - (-\frac{20}{21}) = \frac{20}{21}$

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$=> \frac{9}{5} \times \frac{1}{\frac{7}{5} }$

$=> \frac{9}{5} \times \frac{5}{7}$

$=> \frac{9}{7}$

Now, find the product of $\frac{9}{7}$ & $\frac{20}{21}$

$=> \frac{9}{7} \times \frac{20}{21}$

$=> \frac{180}{147}$

3 0

3 years ago

8-2w=6w-8 help lol!!!!!!!!!!!

NNADVOKAT [17]

W = 2. How do we find this out?

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