Well the heat that is needed to raise the temperature of 10g of water by 17oC is
Answer: Total work produced = 1.355 × 10^5 KJ
Explanation:
Substance :H2O, V1=1m3
State1= sat. liquid, T1=200°C, x1=0
State2= sat.mixture, T1=200°C, x2= 0.8
v1=vf=0.001157m3/kg, vg=0.12721m3/kg
P1=P2=Psat. =1554.9 KPa
v2= vf+x2 (vg-vf) =0.001157 +0.8(0.12721-0.001157)=0.102m3/kg
V2= V1×v2/v1 = 1× 0.102/0.001157 =88.159m3
W= P(V1-V2) =1554.9(88.152- 1) = 1.355x10^5KJ
it is C....................
Following the definition of the center of mass, "In physics, the center of mass of a distribution of mass in space is the unique point where the weighted relative position of the distributed mass sums to zero."
(see explanation below)
Answer:
1.2 kg m²
Explanation:
Angular momentum is conserved:
L = L
Iω = Iω
(4.6 kg m²) (1.0 rev / 1.5 s) = I (2.5 rev/s)
I = 1.2 kg m²