<u>Given:</u>
Temperature T = 0.20 μK
<u>To determine:</u>
The de Broglie wavelength of Rubidium atoms
<u>Explanation:</u>
The de broglie wavelength (λ) is related to the temperature (T) as:
λ = h/√2πmkT -----(1)
where h = Planck's constant = 6.626*10⁻³⁴ Js
m = mass of Rubidium = 85.47 amu * 1.66*10⁻²⁷ kg/ 1 amu = 1.419*10⁻²⁵ kg
k = Boltzmann constant = 1.38*10⁻²³ J.K⁻¹
T = temperature = 0.2 μK = 0.2 *10⁻⁶ K
Substituting these values in equation (1) we get:
λ = 6.626*10⁻³⁴ Js/√2π * 1.419*10⁻²⁵ kg * 1.38*10⁻²³ J.K⁻¹ * 0.2 *10⁻⁶ K
= 4.224*10⁻⁷ m
Ans: The de Broglie wavelength is 4.224*10⁻⁷ m
A wave looses its power as it comes to shore because it gets less deeper every second it gets closer to shore
Visible light has a wavelength of 400-700nm, which means light microscopes cannot see anything smaller than this. Atoms are much smaller than this, so they are not visible to light microscopes.
Answer:
Electric field,
in the direction of gravity.
Explanation:
Given that,
Mass of the ball, m = 0.15 g
Charge on the ball, ![q=-2\ nC=-2\times 10^{-9}\ C](https://tex.z-dn.net/?f=q%3D-2%5C%20nC%3D-2%5Ctimes%2010%5E%7B-9%7D%5C%20C)
The ball is placed inside a uniform electric field, and is suspended against the force of gravity such that,
![mg=qE](https://tex.z-dn.net/?f=mg%3DqE)
![E=\dfrac{mg}{q}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7Bmg%7D%7Bq%7D)
![E=\dfrac{0.15\times 10^{-3}\times 9.8}{-2\times 10^{-9}}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7B0.15%5Ctimes%2010%5E%7B-3%7D%5Ctimes%209.8%7D%7B-2%5Ctimes%2010%5E%7B-9%7D%7D)
The electric field will be acting in the direction of gravity. Hence, this is the required solution.
Answer:
mass of the solid is 10.8kg
Explanation:
Weight of the solid=w=18.36N
Force of gravity on the surface of the moon=g=1.71Nkg^-1
Mass of the solid on the moon=m=?
as we know that
weight=mass×force of gravity
here we have to find the mass
=mass
mass=![\frac{18.36N}{1.7Nkg^-1}](https://tex.z-dn.net/?f=%5Cfrac%7B18.36N%7D%7B1.7Nkg%5E-1%7D)
Mass of the solid=10.8kg
i hope it will help you