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S_A_V [24]
3 years ago
5

The___ is composed of Earth's crust and solid upper mantle

Physics
2 answers:
r-ruslan [8.4K]3 years ago
4 0
The inner core is composed of the earth's crust and solid upper mantle.
antiseptic1488 [7]3 years ago
3 0
B. Outer core because the earth's crust and solid mantel are the first two layers
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2 years ago
Elements that easily transmit electricity and heat display the property known as conductivity.
Musya8 [376]


True.

Conductivity is the ability to transmit heat, electricity or sound. Conductivity is a physical property.

A physical property is one which can be measured  or observed without changing the composition or identity of a the substance.

Conductivity is a physical property because the composition of the substance does not change.

A copper wire is still  a copper wire when it is conducting electricity. Like wise, an aluminum rod is still an aluminum rod when heated. It is conducting heat but the heat does not change it, it is still  an aluminum rod during the whole process.

7 0
3 years ago
Read 2 more answers
Which law represents the thermodynamic statement of the conservation of energy of a system
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3 0
3 years ago
Sam shared with his class that he lives on Oak Street. Sam is likely how old?
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4 0
3 years ago
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A cylindrical capacitor has an inner conductor of radius 2.7 mmmm and an outer conductor of radius 3.1 mmmm. The two conductors
Mars2501 [29]

Answer:

(A) Capacitance per unit length = 4.02 \times 10^{-10}

(B) The magnitude of charge on both conductor is Q = 4.22 \times 10^{-19} C and the sign of charge on inner conductor is +Q and the sign on outer conductor is -Q

Explanation:

Given :

Radius of inner part of conductor  (R_{1}) = 2.7 \times 10^{-3} m

Radius of outer part of conductor  (R_{2}) = 3.1 \times 10^{-3} m

The length of the capacitor (l) = 3 \times 10^{-3} m

(A)

Capacitance is purely geometrical property. It depends only on length, radius of conductor.

From the formula of cylindrical capacitor,      

     C = \frac{2\pi\epsilon_{o} l }{ln\frac{R_{2} }{R_{1} } }

Where, \epsilon_{o} = 8.85 \times 10^{-12}

But we need capacitance per unit length so,

     \frac{C}{l}  = \frac{2\pi\epsilon_{o}  }{ln\frac{R_{2} }{R_{1} } }

capacitance per unit length = \frac{6.28 \times 8.85 \times 10^{-12} }{ln(1.148)} = 4.02 \times 10^{-10}

(B)

The charge on both conductors is given by,

     Q = C \Delta V

Where, C = capacitance of cylindrical capacitor and value of C = 12.06 \times 10^{-13} F, \Delta V = 350 \times 10^{-3} V

∴ Q = 4.22 \times 10^{-19} C

The magnitude of charge on both conductor is same as above but the sign of charge is different.

Charge on inner conductor is +Q and Charge on outer conductor is -Q.

8 0
3 years ago
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