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S_A_V [24]
3 years ago
5

The___ is composed of Earth's crust and solid upper mantle

Physics
2 answers:
r-ruslan [8.4K]3 years ago
4 0
The inner core is composed of the earth's crust and solid upper mantle.
antiseptic1488 [7]3 years ago
3 0
B. Outer core because the earth's crust and solid mantel are the first two layers
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Which situation is the best example of translational motion?.
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 a block sliding down a ramp,a leaf blowing across a field

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1. Stops: Using the information learned in this course, explain three things you will not do when driving.
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Don't text while driving
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It's a duty of the AHJ to
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The duty of the AHJ is to: (C). review installation designs and determine if they fall under Code jurisdiction

<h3>Meaning of AHJ</h3>

AHJ can be defined as that means Authority Having Jurisdiction

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7 0
2 years ago
A photon has 3.4 × 10–18 joules of energy. Planck’s constant is 6.63 × 10–34 J•s.
hodyreva [135]
Ok i will answer for real this time. Please give me brainliest.
<span>The Answerr is:
5.12*10^15. Since e=h*f, f=e/h. 3.4*10^(-18)/h.
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5 0
3 years ago
The potential energy stored in the compressed spring of a dart gun, with a spring constant of 32.50 N/m, is 0.640 J. Find by how
liraira [26]

Answer:

A

   x = 0.198456 \ m

B

    h  =  1.3061 \  m

C

 v =  5.06 \  m/s

D

  d = 4.0273 \  m

Explanation:

Considering the first question

From the question we are told that

   The spring constant is  k  =  32.50 N/m

    The potential energy is  PE  =  0.640 \ J

Generally the potential  energy stored in spring  is mathematically represented as   PE  =  \frac{1}{2}  *  k  *  x^2

=>    0.640=  \frac{1}{2}  * 32.50  *  x^2  

=>    x = \sqrt{0.03938}  

=>    x = 0.198456 \ m  

Considering the second question

 From the question we are told that

   The mass of the dart is  m =  0.050 kg

Generally from the law of energy conservation

         PE =  mgh

=>       0.640   =  0.050 *  9.8  *  h

=>      h  =  1.3061 \  m

Considering the third  question

   The height at which the dart was fired horizontally is  H  =   3.90\  m

Generally  from the law of energy conservation

         PE = KE

Here  KE is kinetic energy of the dart which is mathematical represented as

     KE  =  \frac{1}{2}  *  mv^2

=>      0.640 =  \frac{1}{2}  * 0.050 *  v^2

=>       v^2 = 25.6

=>       v =  5.06 \  m/s

Considering the fourth question

Generally the total time of flight of the dart is mathematically represented as

       t  =  \frac{ 2 *  H }{g}

=>     t  =  \frac{ 2 * 3.90 }{9.8 }

=>     t  =  0.7959 \ s

Generally the  horizontal distance from the equilibrium position to the ground is  mathematically represented as

       d =  v  *   t

=>     d = 5.06  *   0.7959

=>     d = 4.0273 \  m

5 0
3 years ago
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