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otez555 [7]
3 years ago
15

Select the equation that contains the point (4, -8), and in which the graph of the line has a positive slope.

Mathematics
1 answer:
BaLLatris [955]3 years ago
5 0
Okay, let me just make this a little clearer. Hopefully, this is what you meant:

A. y - 8 = -4(x + 4)
B. y - 8 = 4(x + 4)
C. y + 8 = 4(x - 4)
D. y + 8 = -4(x - 4)

--

This can also be written as y2 - y1 = m(x2 - x1).

Your M is your slope. 

Both A and D have their m as a negative 4. Because you are looking for a positive slope, immediately cancel those answers.

* note that you could have also put them in a more standard form and discovered m which is the x in bx. 

Now, you are looking for an equation that contains (4,-8).

Because it is written as y2-y1, your y's are actually points if you were to find another slope or something. This part is a bit hard to explain, but -8 is only found in the y coordinate place in answer B. Your answer would be B. For more explanation on that, there's this great site called coolmath.com and if you search for finding the equation of two points, it explains it much better on there, but I would not want to plagiarize. 

The answer is B.


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Answer:

x = -20/11

Step-by-step explanation:

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I need help with that
wariber [46]

Answer:

Domain: x \leq 8

Step-by-step explanation:

All real numbers minors than or equal to 8

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Not sure how to solve this
Hoochie [10]

Answer:

  (x, y) = (0, -14), (2, -8), (3, -5)

Step-by-step explanation:

Put the given values into the equation and solve.

<u>x = 0</u>

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  -8 = 3x -14

  6 = 3x . . . . . . add 14

  2 = x . . . . . . . divide by 3

<u>x = 3</u>

  y = 3·3 -14 = -5

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The ordered pairs in your table are ...

  (x, y) = (0, -14), (2, -8), (3, -5)

_____

<em>Comment on the approach</em>

In this problem, you are only asked for one x-value for a given y-value. If there were more, you would solve the equation generically (x = (y+14)/3) and use that to compute the desired values of x.

3 0
4 years ago
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Find the equation of the line parallel to the graph of 4x-5y=-1 that contains the point (1,3)
rewona [7]

Answer:

To find the equation of the line parallel to the graph, first of all find the slope of the graph by making y the subject of the formula and comparing the resulting equation with y = mx + c , knowing fully well that m stands for the slope.

So, from the equation of the graph give, y = 4x/5 +1/5, therefore the slope is 4/5. For a line to be parallel to the graph then they must have the same slope, to find the equation of the line at the given point, then we use the formula

y - y1 = m ( x - x1 )

y - 3  = 4/5 ( x - 1 )

multiply through by 5

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5y - 15 = 4x - 4

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so,  5y - 4x = 11 is the equation

Step-by-step explanation:

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