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gulaghasi [49]
3 years ago
11

How to solve for x7/4x - 3 = 2 + 9/2x​

Mathematics
2 answers:
DochEvi [55]3 years ago
6 0

Answer:

X = 11/20

Step-by-step explanation:

7/4x-3=2+9/2x

We move all terms to the left:

7/4x-3-(2+9/2x)=0

Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R

Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R

We add all the numbers together, and all the variables

7/4x-(9/2x+2)-3=0

We get rid of parentheses

7/4x-9/2x-2-3=0

We calculate fractions

14x/8x^2+(-36x)/8x^2-2-3=0

We add all the numbers together, and all the variables

14x/8x^2+(-36x)/8x^2-5=0

We multiply all the terms by the denominator

14x+(-36x)-5*8x^2=0

Wy multiply elements

-40x^2+14x+(-36x)=0

We get rid of parentheses

-40x^2+14x-36x=0

We add all the numbers together, and all the variables

-40x^2-22x=0

a = -40; b = -22; c = 0;

Δ = b2-4ac

Δ = -222-4·(-40)·0

Δ = 484

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

x1=−b−Δ√2ax2=−b+Δ√2a

Δ−−√=484−−−√=22

x1=−b−Δ√2a=−(−22)−222∗−40=0−80=0

x2=−b+Δ√2a=−(−22)+222∗−40=44−80=−11/20

Ber [7]3 years ago
5 0

Answer:

x = -20/11

Step-by-step explanation:

and how -(11 x)/4 - 5 = 0

1/4 (7 x - 12) = 1/2 (9 x + 4)

hope this helps

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Why cant the a value in the standard form of a quadratic function ax^2+bx+c=0 be equal to 0?
alexandr1967 [171]

Answer:

  the equation is no longer quadratic

Step-by-step explanation:

A quadratic equation is a polynomial equation in which the highest-degree term has degree 2.

<h3>What happens when <em>a = 0</em>?</h3>

The value a=0 makes the squared term disappear. If 'a' is zero, the equation becomes a linear equation, not a quadratic equation:

  bx +c = 0

7 0
2 years ago
Identify the 'a' value: y = 16x2 -8x-24
dolphi86 [110]

Answer: The value of a in the equation is 16

Step-by-step explanation:

The quadratic equation y= 16x2-8x-24

From y= ax2+bx+c

Therefore, a=16; b=-8; c-24

5 0
3 years ago
Mattie uses the discriminant to determine the number of zeros the quadratic equation 0 = 3x2 – 7x + 4 has. Which best describes
r-ruslan [8.4K]

Answer:

The equation has two zeros because the discriminant is greater than 0.

Step-by-step explanation:

3x^2 – 7x + 4

a=3   b = -7   c=4

The discriminant is

b^2 -4ac

(-7)^2 - 4(3)(4)

49 - 48

1

Since the discriminant is greater than zero, there are two real solutions

5 0
3 years ago
Please help me please
san4es73 [151]

Answer:

A= 5278.34 in ²

Step-by-step explanation:

A= r² × 3.14 (pi)

Radius = Diameter ÷ 2

82 ÷ 2 = 41

41²= 1681

1681 x 3.14 = 5278.34

hope this helps

7 0
3 years ago
Write an equation of a line that is perpendicular to the line y=2/3x and passes through origin
sesenic [268]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above anyway?

\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}

so we're really looking for the equation of a line whose slope is -3/2 and runs through (0,0).

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{3}{2}}(x-\stackrel{x_1}{0})\implies y=-\cfrac{3}{2}x

7 0
3 years ago
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