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3 years ago

How to solve for x7/4x - 3 = 2 + 9/2x

Mathematics

2 answers:

DochEvi [55]3 years ago

6 0

Answer:

X = 11/20

Step-by-step explanation:

7/4x-3=2+9/2x

We move all terms to the left:

7/4x-3-(2+9/2x)=0

Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R

Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R

We add all the numbers together, and all the variables

7/4x-(9/2x+2)-3=0

We get rid of parentheses

7/4x-9/2x-2-3=0

We calculate fractions

14x/8x^2+(-36x)/8x^2-2-3=0

We add all the numbers together, and all the variables

14x/8x^2+(-36x)/8x^2-5=0

We multiply all the terms by the denominator

14x+(-36x)-5*8x^2=0

Wy multiply elements

-40x^2+14x+(-36x)=0

We get rid of parentheses

-40x^2+14x-36x=0

We add all the numbers together, and all the variables

-40x^2-22x=0

a = -40; b = -22; c = 0;

Δ = b2-4ac

Δ = -222-4·(-40)·0

Δ = 484

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

x1=−b−Δ√2ax2=−b+Δ√2a

Δ−−√=484−−−√=22

x1=−b−Δ√2a=−(−22)−222∗−40=0−80=0

x2=−b+Δ√2a=−(−22)+222∗−40=44−80=−11/20

Ber [7]3 years ago

5 0

Answer:

x = -20/11

Step-by-step explanation:

and how -(11 x)/4 - 5 = 0

1/4 (7 x - 12) = 1/2 (9 x + 4)

hope this helps

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The statistic calculated is given by t=3.3

Since is a one-side upper test the p value would be:

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b) $df=n-1=8-1=7$

The statistic calculated is given by t=1.8

Since is a one-side upper test the p value would be:

$p_v =P(t_{7}>1.8)=0.057$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

c) $df=n-1=26-1=25$

The statistic calculated is given by t=-0.6

Since is a one-side upper test the p value would be:

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So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation

$\bar X$ represent the sample mean

$s$ represent the standard deviation for the sample

$n$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the true mean is higher than 20, the system of hypothesis would be:

Null hypothesis: $\mu \leq 20$

Alternative hypothesis: $\mu > 20$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

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The statistic calculated is given by t=3.3

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So since the p value is lower than the significance level $pv$ we reject the null hypothesis.

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How to solve for x7/4x - 3 = 2 + 9/2x​

How to solve for x7/4x - 3 = 2 + 9/2x