Question

Solve 58 - 10x ≤ 20 + 9x

Answer 1

Answer: $x\geq\dfrac{38}{9}$

Step-by-step explanation:

The given inequality : $58 - 10x \leq 20 + 9x$

To solve the given inequality  , we first add 10x on both the sides , we get

$58-10x+10x\leq20+9x+10x\\\\\Rightarrow\ 58\leq20+19x$

Subtract 20 on both the sides , we get

$58-20\leq20+9x-20\\\\\Rightarrow\ 38\leq9x\text{ or }9x\geq38$

Then, divide 9 on both sides , we get

$x\geq\dfrac{38}{9}$

Hence, the solution of the given inequality will be $x\geq\dfrac{38}{9}$

Answer 2

 the answer is x=2 i hope this answers your problem