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Novosadov [1.4K]
3 years ago
8

I need help assp this is due tmr please help me!

Mathematics
1 answer:
Ede4ka [16]3 years ago
3 0
C=4.95p+32.5
p is the number of channels, and each is 4.95. So, 4.95 * p. The flat rate is 32.50, so 32.5 is added regardless of the channels.
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What is tan D? <br> 5/13 <br> 13/5 <br> 5/12 <br> 12/5
Snezhnost [94]
The answer is 12/5
Remember: Soh;opposite over Hypotenuse Cah; Adjacent over Hypotenuse   Toa; Opposite over Adjacent. SOH CAH TOA

Hope this helps! :)
5 0
3 years ago
2 less than five times a number.
Reika [66]

Answer:

X will be the number.  

5 times that number X is 5X

2 less than 5 times the number is 5X - 2

Hope this helps! Plz mark brainliest! (づ ̄3 ̄)づ╭❤~

8 0
3 years ago
Read 2 more answers
I really don't know can someone help me
crimeas [40]
               6 + 4 ÷ 2

The "order of operations" (which you learned a long time ago
if you're in high school now) says that division should be done
before addition.

So do the division:        4 ÷ 2 = 2

Now you have                6 + 2

Now do the addition:     6 + 2 = 8 .
8 0
3 years ago
Read 2 more answers
Just an easy question for 100 Points!<br> Check my other easy 100 point questions :)
skad [1K]

#1

y=x+5

  • Shifted 5units left

#2

y=3/8

  • Horizontally Streched by a factor 8/3 parallel to x axis

#3

  • y=-x-2

Reflection by y axis as x will be negative and shifting 2 units right

#4

y=6x+1

  • vertically streched by a factor 6 and shifting 1 units left

#5

y=x-11

  • Shifting 11 units left

#6

y=8x

Horizontally streched by 1/8 factor

3 0
2 years ago
What is the average rate of change of f over the interval -1 on a separate sheet of paper and upload the work as a photo. Show a
Anarel [89]

Answer:

Average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

Step-by-step explanation:

We need to find average rate of change of f over the interval -1 < x < 1

The function given is: f(x)= x^2-x-1

The formula used to find average rate of change is:

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}

We have, a = -1 and b = 1

Finding f(b) when b=1

f(x)=x^2-x-1\\f(1)=(1)^2-(1)-1\\f(1)=1-1-1\\f(1)=-1

Now, finding f(a), when a= -1

f(x)=x^2-x-1\\f(-1)=(-1)^2-(-1)-1\\f(1)=1+1-1\\f(-1)=2-1\\f(-1)=1

Now, putting values and finding average rate of change

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}\\Average\:rate\:of\:change=\frac{f(1)-f(-1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-(1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-1}{1+1}\\Average\:rate\:of\:change=\frac{-2}{2}\\Average\:rate\:of\:change=-1

So, average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

4 0
3 years ago
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