Answer:
range of f(x) = [-4, -2) ∪ [2, 8)
a+b+c+d = -4
Step-by-step explanation:
The graph is attached. The range is the vertical extent of the function. It is defined at f(0) = -4 and f(2) = 2.
The limits f(2-) and f(4-) are -2 and 8, respectively, so the graph has open circles there. These are the ends of the two half-open intervals that make up the range of the function.
The portion of the graph in the domain [4, 7) is included in the range [2, 8), so no special treatment is needed for that piece of the function.
2^x = 32
x = 5
Hope this helps!
Answer:-1/32
Step-by-step explanation:
First term=a=1024
Common ratio=r=-512/1024
r=-1/2
Using them formula
Tn=a x r^(n-1)
T16=1024 x (-1/2)^(16-1)
T16=1024 x (-1/2)^15
T16=1024 x -1/32768
T16=-1024/32768
T16=-1/32
Answer:
Step-by-step explanation:
✓ A. (0, 0) [y < 3x + 2 → 0 < 2]
× B. (0, 2) [y < 3x + 2 → 2 < 2]
✓ C. (1, 4) [y < 3x + 2 → 4 < 5]
× D. (1, 7) [y < 3x + 2 → 7 < 5]
✓ E. (2, 6) [y < 3x + 2 → 6 < 8]
× F. (2, 8) [y < 3x + 2 → 8 < 8]
You reflect point A over the x-axis, double the distance from point a to the x-axis, then give the coordinates.
ex/ point A to the x-axis: 6, reflection: 12. coordinates (-6, 5)
