6x-2x^2 would be the answer
Answer:
The answer to the question is
She invested
Php2700.00 at 8 % and
Php 20,400.00 at 11 %
Step-by-step explanation:
To solve the question we note that
Simple interest is given by
where
P= Principal, R = Rate and T = Time
If we call the first part P₁, T₁, and R₁ and the second part
P₂, T₂, and R₂
Then 
= 2700×0.08×1 + P₂×0.11×1 = 2460 which gives
2244÷0.11 = P₂ or P₂ = Php 20,400.00
That is she invested
Php2700.00 at 8 % and
Php 20,400.00 at 11 %
The required value after simplification of the s = -16/3. None of these are correct.
Given that,
To simplify
and to find the value of s in
.
<h3>What is simplification?</h3>
The process in mathematics to operate and interpret the function to make the function simple or more understandable is called simplifying and the process is called simplification.
Simplification,
![=[\frac{x^{2/3}x^{-1/2}}{x\sqrt{x^3}\sqrt[3]{x}}]^2\\= \frac{x^{4/3}x^{-1}}{x^2x^3*{x}^{2/3}}\\= \frac{x^{1/3}}{x^{17/3}}\\=x^{-16/3}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7Bx%5E%7B2%2F3%7Dx%5E%7B-1%2F2%7D%7D%7Bx%5Csqrt%7Bx%5E3%7D%5Csqrt%5B3%5D%7Bx%7D%7D%5D%5E2%5C%5C%3D%20%5Cfrac%7Bx%5E%7B4%2F3%7Dx%5E%7B-1%7D%7D%7Bx%5E2x%5E3%2A%7Bx%7D%5E%7B2%2F3%7D%7D%5C%5C%3D%20%5Cfrac%7Bx%5E%7B1%2F3%7D%7D%7Bx%5E%7B17%2F3%7D%7D%5C%5C%3Dx%5E%7B-16%2F3%7D)
Comparing with 
s = -16/3
Thus, the required value of the s = -16/3. None of these are correct.
Learn more about simplification here: brainly.com/question/12501526
#SPJ1
Hey you're using Apex xD
Answer is D.
Here's an example
6= 3x2
Just divide. 6/2 = 3 <span />
In fact, this problem belongs to the chemistry section. Recall that many other sciences require mathematical calculations. The problem will belong to Mathematics only if no knowledge of other sciences are required to solve the problem.
Solubility for the given substances is measured in grams per 100 g of water at a particular temperature (20 deg.C).
This means that the mass (assumed to be the solute) will not change the solubility, just the minimum quantity of solvent (water) will.
Thus the solubility of sodium chloride will remain L=36 g/100g H2O for any quantity of solute. Similarly, the solubility of lead nitrate will remain as K=54 g/100 g H2O.
The reason that they remain constant is because the quantity of solvent (water) is fixed at 100 g. Varying amount of solute will affect the quantity of solvent required, but not the solubility.
I'll leave it to you to calculate the difference between K & L.