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DedPeter [7]
2 years ago
14

the sides of a rectangle are 25 cm and 8 cm. what is the measure, to the nearest degree, of the angle formed by the short side a

nd a diagonal of the rectangle?

Mathematics
1 answer:
ycow [4]2 years ago
8 0

Answer:

72°

Step-by-step explanation:

The lengths 25 cm and 8 cm are the sides of the rectangle.

See the attached diagram of rectangle ABCD.

Now, let us assume the diagonal AC makes x° angle with the shorter side BC i.e.∠ BCA = x°

So, using trigonometry we can write

\tan x = \frac{AB}{BC} = \frac{25}{8} = 3.123

⇒ x = \tan ^{-1} (3.125) = 72.25 degrees ≈ 72 degrees {Rounded to nearest degree} (Answer)

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Answer:

Simplifying  the expression: 2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3) we get \mathbf{42x-100y-360}

Step-by-step explanation:

We need to simplify the expression: 2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3)

First we will solve terms inside the bracket

2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3)

Converting mixed fraction 1\frac{1}{2} y into improper fraction, we get: \frac{3}{2}y

Replacing the term:

2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-\frac{3}{2}y +3)

Now, taking LCM of: 5,3,4,2 we get 60

Now multiply 60 with each term inside the bracket

2(\frac{3}{5}x\times60+\frac{2}{3}y\times60-\frac{1}{4}x\times60-\frac{3}{2}y\times60 +3\times60)\\2(3x\times12+2y\times20-1x\times15-3x\times30-3\times60)\\2(36x+40y-15x-90y-180)

Now, combine like terms

2(36x-15x-90y+40y-180)\\2(21x-50y-180)

Now, multiply all terms with 2

42x-100y-360

So, Simplifying  the expression: 2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3) we get \mathbf{42x-100y-360}

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