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bekas [8.4K]
3 years ago
11

How many hydrogen ions are in 1 liter of stomach acid? (Hint: Avogadro’s number). Show your work and remember to put your answer

in regular number form (NOT scientific notation).
Chemistry
1 answer:
ch4aika [34]3 years ago
3 0

Answer:

96,532,000,000,000,000,000,000 ions.

Explanation:

  • Assume the highest concentration of HCl in the stomach (160 mmol/L) that is in the canaliculi.
  • This means that 1.0 L of the stomach acid contains 0.160 mol.
  • Every 1.0 mole of HCl contains Avogadro’s number of molecules (6.022 x 10²³) molecules.
  • Every 1.0 molecule of HCl contains 1.0 H⁺ ion.

<u><em>Using cross multiplication:</em></u>

1.0 mole of HCl → 6.022 x 10²³ H⁺ ions.

0.160 mole of HCl → ??? H⁺ ions.

∴ The no. of H⁺ ions in 1 liter of stomach acid = (6.022 x 10²³ H⁺ ions)(0.160 mole of HCl) / (1.0 mole of HCl) = 9.6352  x 10²² ions = 96,532,000,000,000,000,000,000 ions.

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The heat of combustion of propane, C3H8 (g) is -2057 kJ/mol. What would be the enthalpy change if enough propane was burned to g
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Considering the reaction stoichiometry, the enthalpy change if enough propane was burned to give off 12 moles of carbon dioxide gas is 8228 kJ.

The balanced reaction is:

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(l)

The heat of combustion of propane, C₃H₈, is -2057 kJ/mol. This is, 2057 kJ is released for every 1 mol C₃H<u>₈</u>.

So to determine the enthalpy change if enough propane was burned to emit 12 moles of carbon dioxide, you must take into account the stoichiometry of the reaction.

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

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Then you can apply the following rule of three: if by stoichiometry 3 moles of CO₂ are produced by 1 mole of C₃H₈, 12 moles of CO₂ are produced by how many moles of C₃H₈?

amount of moles of C_{3} H_{8} =\frac{12 moles of CO_{2}x1 mole of C_{3} H_{8} }{3 moles of CO_{2}}

<u><em>amount of moles of C₃H₈= 4 moles</em></u>

So to determine the enthalpy change, you can apply the following rule of three: If for each mole of C₃H₈ 2057 kJ are released, for 4 moles of C₃H₈ how much heat is released?

Heat released=\frac{4 molesx2057 kJ}{1 mole}

<u><em>Heat released= 8228 kJ</em></u>

The enthalpy change if enough propane was burned to give off 12 moles of carbon dioxide gas is 8228 kJ.

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