Answer:
Ethanol
Explanation:
Hello,
Since the hexanes and the ethyl acetate are mostly composed by C-C, C-H and for the ester C-O bonds which are apolar, just the ethanol which has one O-H bond could be classified as polar, allowing H-bridges to be present.
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Answer:
b. ΔS° > 0, ΔH° < 0
Explanation:
According the equation of Gibb's free energy -
∆°G = ∆°H -T∆°S
∆°G = is the change in gibb's free energy
∆°H = is the change in enthalpy
T = temperature
∆°S = is the change in entropy .
And , the sign of the Δ°G , determines whether the reaction is Spontaneous or non - Spontaneous or at equilibrium ,
i.e. ,
if
- Δ°G < 0 , the reaction is Spontaneous
- Δ°G > 0 , the reaction is non - Spontaneous
- Δ°G = 0 , the reaction is at equilibrium
The reaction has the value for ∆°H < 0 i.e. negative, and ∆°S > 0 i.e. , positive
Now ,
∆°G = ∆°H -T∆°S
= ( - ∆°H ) - T( + ∆°S )
= ( - ∆°H ) - T( ∆°S )
∆°G = negative
Hence ,
Δ°G < 0 , the reaction is Spontaneous .
Moles of Carbon dioxide : 13.5
<h3>Further explanation</h3>
Given
4.5 moles propane
Required
moles of Carbon dioxide
Solution
Reaction(Combustion of Propane) :
<em>C₃H₈(g)+5O₂(g)→3CO₂(g)+4H₂O(g)</em>
In a chemical equation, the reaction coefficient shows the mole ratio of the reacting compounds (either in reactants or products)
From the equation, mol ratio of Propane(C₃H₈) : Carbon dioxide(CO₂) : 1 : 3, so mol CO₂ :
= 3/1 x mol Propane
= 3 x 4.5 moles
= 13.5 moles
