The number of kilograms of fuel that are contained in one canister is 1.03 Kilograms
calculation
mass = density x volume
Density= 0.710 g/cm³
volume = 1.45 L
convert 1.45 l into cm³ to make the units uniform
that is 1 L= 1000 cm³
1.45 L= cm³
by cross multiplication
= (1.45 L x 1000 cm³) / 1 L = 1450 cm³
mass is therefore = 0.710g/cm³ x 1450 cm³ =1029.5 grams
convert grams to Kg
1 kg = 1000 grams
? kg =1029.5 grams
by cross multiplication
= (1 kg x 1029.5 grams) /1000 grams = 1.0295 Kg ≅1.03 kg
Answer:
its 2p
Explanation:
In a neutral carbon atom, the 1s sublevel has one orbital with two electrons with opposite spins, represented by the arrows pointing in opposite directions. The 2s sublevel also has one orbital with two electrons, also with opposite spins. The 2p sublevel has three orbitals.
(i don"t understand this i just looked it up ._.
Answer:
About 277 Kelvin
Explanation:
Take the celcius, and add 273.15 to it
4°C + 273.15 = <u>277.15K</u>
And round the answer to the nearest whole
277.15K ≈ 277K
Answer:
The concentration of fructose-6-phosphate is 1.50x10⁻³M
Explanation:
Gibbs Free energy, ΔG°, is defined as:
ΔG° = -RTln K
<em>Where ΔG° = 1670J/mol</em>
<em>R is gas constant = 8.314J/molK</em>
<em>T is absolute temperature (25°C + 273.15 = 298.15K)</em>
Thus, equilibrium constant, k, is:
1670J/mol = -8.314J/molK* 298.15K ln K
-0.6737 = ln K
0.5098 = K
K of the reaction:
G6P ⇄ F6P
is:
K = 0.5098 = [F6P] / [G6P]
As [G6P] is 2.95x10⁻³M:
0.5098 = [F6P] / [2.95x10⁻³M]
[F6P] = 1.50x10⁻³M
<h3>The concentration of fructose-6-phosphate is 1.50x10⁻³M</h3>
