Answer:
last one is your answer.....
The nuclear equation :
₈₂²¹⁴Pb ⇒ ₈₃²¹⁴Bi + ₋₁⁰e
<h3>Further explanation
</h3>
Given
₈₂²¹⁴Pb
beta β ₋₁e⁰ particles
Required
Nuclear equation
Solution
Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,
-
alpha α particles ₂He⁴
- beta β ₋₁e⁰ particles
- gamma particles ₀γ⁰
- positron particles ₁e⁰
- neutron ₀n¹
The principle used is the sum of the atomic number and mass number before and after the decay reaction is the same
The reaction
₈₂²¹⁴Pb ⇒ X + ₋₁⁰e
The element X has
-the atomic number = 82 + 1 = 83
-the mass number = 214
In the periodic system, the element with atomic number 83=Bismuth
<span>Ans- bond with the highest bond energy is for ( C=C \rightarrow 620 (kJ/mol)
N=N \rightarrow 418 (kJ/mol)
Si=O \rightarrow 452 (kJ/mol)
O=O \rightarrow 498.7 (kJ/mol)
C=N \rightarrow 615 (kJ/mol)
C=C \rightarrow 620 (kJ/mol)</span>
1 mole C₆H₁₂O₆ ------------- 6 moles oxygen
3 moles C₆H₁₂O₆ ----------- X
X = (3×6)/1
X = 18 moles
The balanced chemical reaction is:
C3H8 + 5O2 = 3CO2 + 4H2O
We are given the amount of C3H8 to be used for the reaction. This will be the starting point for the calculations.
73.7 g C3H8 (1 mol C3H8 / 44.11 g C3H8) ( 5 mol O2 / 1 mol C3H8 ) ( 32 g O2 / 1 mol O2 ) = 267.3 g O2
