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velikii [3]
3 years ago
15

What are the correct half reactions for the following reaction: Cu2+ + Mg -> Cu + Mg2+

Chemistry
2 answers:
romanna [79]3 years ago
6 0

Answer:

Mg→Mg2++2e− Cu2++2e−→Cu

Explanation:

Educere/ Founder's Education Answer

Sunny_sXe [5.5K]3 years ago
4 0

Answer:

Cu2 + 2Mg-> 2Cu+ Mg2

Explanation:

Balance the equation and make sure both the reactant and the products are the same

Hope it will be helpful

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The definition of the acceleration states that an object accelerates when it <br> PLEASE HELP!!!
velikii [3]

Maybe this can help.

In mechanics, speed increase is the pace of progress of the speed of an article regarding time (acceleration). Speed increases are vector amounts (in that they have greatness and direction). The direction of an item's speed increase is given by the direction of the net power following up on that article. The size of an item's speed increase, as depicted by Newton's Second Law, is the consolidated impact of two causes:

the net equilibrium of all outer powers acting onto that item — size is straightforwardly relative to this net coming about force;

that article's mass, contingent upon the materials out of which it is made — extent is conversely relative to the item's mass.

6 0
1 year ago
Read 2 more answers
What are two factors that affect the function of enzymes
lapo4ka [179]

Answer:

Temperature

PH

Explanation:

Enzymes are organic catalysts that speeds up the rate of a chemical reaction. Their activities are affected by temperature and pH of the environment among other factors.

  • At extreme temperatures, enzymes can easily be denatured and they will cease to act.
  • At extremes of pH, they can also be adversely affect.

Enzymes generally have temperature and pH window for their activity.

4 0
2 years ago
Use the balanced equation from number four above to determine the limiting reactant if we had a mixture of 5.0 moles of Fe and 4
Tom [10]

Answer:

2Fe + 3O₂  →  2Fe₂O₃

Limiting reactant: O₂

2Fe + O₂ → 2FeO

Limiting reactant: Fe

Explanation:

2Fe + 3O₂  →  2Fe₂O₃

2Fe + O₂ → 2FeO

These are the possible reactions:

In first case, 2 moles of Fe need 3 mol of oyxgen to react

If I have 5 moles of Fe, I will need (5 .3)/2 = 7.5 moles of O₂

Then, the oxygen is my limiting ( I only have 4 moles)

3 moles of O₂ need 2 moles of Fe

If I have 4 moles of O₂, I will need (4 .2)/3 = 2.66 moles (I have 5)

Fe, is the reactant in excess.

For second case, 2 moles of Fe need 1 mol of O₂, to react.

If I have 5 moles of Fe, I will need ( 5 .1) / 2 =2.5 moles of O₂

I have 4 moles of oxygen, so now it is my excess.

1 mol of O₂ need 2 moles of Fe, to react

If I have 4 moles of O₂, I will need the double of amount, 8 moles of Fe.

I have 5 moles, then the Fe is my limtiing reactant.

8 0
2 years ago
A chemist prepares a solution of sodium carbonate by measuring out of sodium carbonate into a volumetric flask and filling the f
Vadim26 [7]

Answer:

The correct answer will be "9.45\times 10^{-5} \ mol/L".

Explanation:

We have:

Moles of solute (Na₂Co₃) = 18.9 \mu \ mol

                                           = 18.9\times 10^{-6}

                               1 \mu \ mol = 10^{-6} \ mol

Now,

The volume of the solution will be:

⇒  0.200 \ L

∴ {1 \ mL=0.001 \ L}

The formula to find the concentration will be:

⇒  Concentration = \frac{moles \ of \ solute \ (mol)}{Volume \ of \ solution \ (L)}

On substituting the given values, we get

⇒                          =\frac{18.9\times 10^{-6}}{0.200}

⇒                          =9.45\times 10^{-5} \ mol/L

8 0
2 years ago
Given 6.23 mol Al find the atoms of Al
swat32

Answer:

The answer is

<h3>3.75 × 10²⁴ atoms of Al</h3>

Explanation:

To find the number of atoms of Al given it's number of moles we use the formula

<h3>N = n × L</h3>

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

n = 6.23 mol

We have

N = 6.23 × 6.02 × 10²³

We have the final answer as

<h3>3.75 × 10²⁴ atoms of Al</h3>

Hope this helps you

3 0
2 years ago
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