2x=5 so 5÷2 = x (2.5)
3y = 4 so 4÷3 = y (1.3 recurring)
4z = 3 so 3÷4 = z (0.75)
implement: 24x2.5x1.3•x0.75
hope i answered right
Answer:
area of shaded portion=56 - 1/2 ×3×4=56-6= 50 yd^2
Answer:

Step-by-step explanation:
![the \: \sqrt[3]{121} \: is \: not \: a \: perfect \: cube \\ but \\ the \: \sqrt{121} = 11 \to \: is \: a \: perfect \: square \\](https://tex.z-dn.net/?f=the%20%5C%3A%20%20%5Csqrt%5B3%5D%7B121%7D%20%20%5C%3A%20is%20%5C%3A%20not%20%5C%3A%20a%20%5C%3A%20perfect%20%5C%3A%20cube%20%5C%5C%20but%20%5C%5C%20the%20%5C%3A%20%20%5Csqrt%7B121%7D%20%20%3D%2011%20%5Cto%20%5C%3A%20is%20%5C%3A%20a%20%5C%3A%20perfect%20%5C%3A%20square%20%5C%5C%20)
I think it is A because i think it is the only one that makes sense
The first thing we must do for this case is to define variables.
We have then:
x: number of slices
y: total cost
We write the linear function that relates the variables.
We have then:

Then, we evaluate the number of slices to find the total cost.
-two slices cost:
We substitute x = 2 in the given equation:

Answer:
two slices = 2.2 $
-ten slices cost:
We substitute x = 10 in the given equation:

Answer:
ten slices = 11 $
-half a slice cost:
We substitute x = 1/2 in the given equation:

Answer:
half a slice = 0.55 $