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3 years ago

Find the quotient: 15x^4y^2-30x^2y^3+45xy/5xy is ____. when this quotient is divided by _the result is x^3y-2xy^2+3

1 answer:

5 0

$\dfrac{15x^4y^2-30x^2y^3+45xy}{5xy}=\dfrac{15x^4y^2}{5xy}-\dfrac{30x^2y^3}{5xy}+\dfrac{45xy}{5xy}\\\\=3x^{4-1}y^{2-1}-6x^{2-1}y^{3-1}+9=3x^3y-6xy^2+9\\\\=3(x^3y-2xy^2+3)\\\\Used:\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\Answer:\\....\underline{3x^3y-6xy^2+9}...\ \ \ ...\underline{3}...$

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Answer:

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For number 6, evaluate the definite integral.

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$\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{(8+2x)^2}}\cdot dx\impliedby \textit{now, let's do some substitution}\\\\
-------------------------------\\\\
u=8+2x\implies \cfrac{du}{dx}=2\implies \cfrac{du}{2}=dx\\\\
-------------------------------\\\\$

$\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{u^2}}\cdot \cfrac{du}{2}\implies \cfrac{1}{2}\int\limits_{0}^{28}\ u^{-\frac{2}{3}}\cdot du\impliedby 
\begin{array}{llll}
\textit{now let's change the bounds}\\
\textit{by using } u(x)
\end{array}\\\\
-------------------------------\\\\
u(0)=8+2(0)\implies u(0)=8
\\\\\\
u(28)=8+2(28)\implies u(28)=64$

$\bf \\\\
-------------------------------\\\\
\displaystyle \cfrac{1}{2}\int\limits_{8}^{64}\ u^{-\frac{2}{3}}\cdot du\implies \cfrac{1}{2}\cdot \cfrac{u^{\frac{1}{3}}}{\frac{1}{3}}\implies \left. \cfrac{3\sqrt[3]{u}}{2} \right]_8^{64}
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\left[ \cfrac{3\sqrt[3]{(2^2)^3}}{2} \right]-\left[ \cfrac{3\sqrt[3]{2^3}}{2} \right]\implies \cfrac{12}{2}-\cfrac{6}{2}\implies 6-3\implies 3$

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2 years ago

Find the quotient: 15x^4y^2-30x^2y^3+45xy/5xy is ________. when this quotient is divided by _____the result is x^3y-2xy^2+3

Find the quotient: 15x^4y^2-30x^2y^3+45xy/5xy is ____. when this quotient is divided by _the result is x^3y-2xy^2+3