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3 years ago

(5h-4)-(h-5) combining like terms

1 answer:

5 0

Distribute the negative throughout the set of parenthesis

5h-4-h+5

Ok, so your like terms are...

5h and -h

-4 and +5

If you rearrange the terms so that the like terms are next to each other, it is easier to combine them:

5h-h-4+5

5h-h=4h

-4+5=1

So, the problem is:

4h+1

Hope that helps :)

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Hey help please math I need help good luck I’ll I’ve point

fredd [130]

Answer:

180 degrees

Step-by-step explanation:

180 degrees would flip the triangle halfway through a full circle. B is A upside down rotated halfway through a full circle.

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2 years ago

A) Dati cinci exemple de numere intregi mai mici ca zero.

12345 [234]

Answer:

Numerele întregi pozitive sunt toate numerele întregi mai mari decât zero: 1, 2, 3, 4, 5, .... Numere întregi negative sunt toate opusele acestor numere întregi: -1, -2, -3, -4, -5, .... Nu considerăm că zero este un număr pozitiv sau negativ. Pentru fiecare număr întreg pozitiv, există un număr întreg negativ, iar acești numere întregi se numesc opuse. De exemplu, -3 este opusul lui 3, -21 este opusul lui 21 și 8 este opusul lui -8. Dacă un număr întreg este mai mare decât zero, spunem că semnul său este pozitiv. Dacă un număr întreg este mai mic decât zero, spunem că semnul său este negativ.

Step-by-step explanation:

4 0

2 years ago

A fruit bowl is shaped like half of a sphere. The radius of the bowl is 15 cm. What is the volume of the bowl?

Delicious77 [7]

Answer:

(4500(Pi))/2 or 7068.585

Step-by-step explanation:

r = 15 cm

volume of a sphere:

(4/3)(Pi)r^3

Therefore:

(4/3)(Pi)15^3

15^3 = 3375

4/3 * 3375 = 4500

and since it is half a sphere (it is a bowl) the answer would be divided by two:

4500(Pi) divided by 2

14137.17 divided by 2

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2 years ago

What is the probability of rolling a four then a three

spayn [35]

Answer:

$\frac{1}{36}$

Step-by-step explanation:

Total possibilities when we a roll a die at a time are 6

given we should have four for first time and then three

let us assume we rolled the dice we may get 1,2,3,4,5,6(any of these) the probability to get 4 is

PROBABILITY= $\frac{\textrm{FAVOURABLE CHANCES}}{\textrm{TOTAL CHANCES}}$

Favourable chances=1

Total chances=6

Probability= $\frac{1}{6}$

the prabability to get 4 in first roll is $\frac{1}{6}$ .

let us assume we rolled the dice for second time again we may get 1,2,3,4,5,6(any of these) the probability to get 3 is

Favourable chances=1

total chances=6

probability= $\frac{1}{6}$

the probability to get 3 in second roll irrespective of first one is $\frac{1}{6}$

the probability to get 4 in first time and then 3 is

The probability to occur both events at a time is multiplication of individual probabilities

So,

probablility to get 4 in first roll= $\frac{1}{6}$

probability to get 3 in second roll= $\frac{1}{6}$

probability to occur both at a same time is = $\frac{1}{6}$ $\times$ $\frac{1}{6}$ = $\frac{1}{36}$

6 0

2 years ago

It's says use compatible numbers to complete the project.then estimate the sum 428+286

OLga [1]

Answer:

Estimate: 700 Answer: 712

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3 years ago