We need to satisfy the following equations:
x*y = 13
x + y = -14
Isolating x from the first equation,
x = -14 - y
Substituting this result into the first equation,
(-14 - y)*y = 13
-14y- y*y = 13
-y² - 14y - 13 = 0
Using the quadratic formula,
![\begin{gathered} y_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ y_{1,2}=\frac{14\pm\sqrt[]{(-14)^2-4\cdot(-1)\cdot(-13)}}{2\cdot(-1)} \\ y_{1,2}=\frac{14\pm\sqrt[]{144}}{-2} \\ y_1=\frac{14+12}{-2}=-13 \\ y_2=\frac{14-12}{-2}=-1 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20y_%7B1%2C2%7D%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D%20%5C%5C%20y_%7B1%2C2%7D%3D%5Cfrac%7B14%5Cpm%5Csqrt%5B%5D%7B%28-14%29%5E2-4%5Ccdot%28-1%29%5Ccdot%28-13%29%7D%7D%7B2%5Ccdot%28-1%29%7D%20%5C%5C%20y_%7B1%2C2%7D%3D%5Cfrac%7B14%5Cpm%5Csqrt%5B%5D%7B144%7D%7D%7B-2%7D%20%5C%5C%20y_1%3D%5Cfrac%7B14%2B12%7D%7B-2%7D%3D-13%20%5C%5C%20y_2%3D%5Cfrac%7B14-12%7D%7B-2%7D%3D-1%20%5Cend%7Bgathered%7D)
Therefore, the solution is:
(2,5) (6,8)
Y2-Y1 divided by X2-X1
8-5=3
———-
6-2=4
so your slope is 3/4
Answer:
1
Step-by-step explanation:
Answer:
the two minus symbols cancel out making it positive 5
Step-by-step explanation:
Answer:
Step-by-step explanation:
You know that anything to the zeroeth power is 1, so the equation is now
-7 * 1, or -7.
