Question

Four times the first of three consecutive even integers is six more than the product of two and the third integer. Find the integers.

Answer 1

The solution to this problem is as follows:

1. Assign your variables.

Let X = first integer
X+2 = second integer
X+4 = third integer

*note: multiples of 2 are added because the problem states that they are consecutive even integers.

2. Formulate the equation

4X = 6 + 2(X+4)
X=7

3. Solve other variables

first integer = 7
second integer = 7+2 = 9
third integer = 7+4 = 11

As you can see, the answers are all odd which means that the given information in the problem should say odd, not even.