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2 years ago

I need help please help me , I don’t know the answer

Mathematics

1 answer:

AlladinOne [14]2 years ago

8 0

Answer:

b = 4 inches, c = ~5.66 inches

Step-by-step explanation:

The triangle is isosceles so b is equal to the adjacent side. Use the Pythagorean theorem to find c.

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1+1 then divide by 8

Gemiola [76]

Answer:

0.25

Step-by-step explanation:

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2 years ago

Find the simple interest on $500 at 6% for one year

Brrunno [24]

600+700 and that’s the answer

8 0

3 years ago

Use the graphs of f and g to solve Exercises 87, 88, and 89.

Nadya [2.5K]

Answers and explanations:

87. The domain of added functions includes the restrictions of both. So the range of the added function in this question is [-4, 3]

88. When finding the domain of a divided function we do the same as adding, but with an extra rule: g can't equal zero. So for this question the domain is (-4, 3)

89. To graph f + g you add the y-values for each x-value. I added a picture to help explain this one!

4 0

3 years ago

Factor each trinomial. Then match the polynomial (term) on the left with its factored form (definition) on the right.

meriva

X² - 8x - 20 factors to give option
B) (x - 10)(x + 2)
x² + 8x - 20 factors to give option
A) (x - 2)(x + 10)
x² - x - 20 factors to give option C) (x - 5)(x + 4)
and x² - 9x - 20 is option D) Prime.

I hope this helps!

8 0

2 years ago

Read 2 more answers

Factor the polynomial, x2 + 5x + 6

patriot [66]

Answer:

Choice b.

$x^{2} + 5\, x + 6 = (x + 3)\, (x + 2)$ .

Step-by-step explanation:

The highest power of the variable $x$ in this polynomial is $2$ . In other words, this polynomial is quadratic.

It is thus possible to apply the quadratic formula to find the "roots" of this polynomial. (A root of a polynomial is a value of the variable that would set the polynomial to $0$ .)

After finding these roots, it would be possible to factorize this polynomial using the Factor Theorem.

Apply the quadratic formula to find the two roots that would set this quadratic polynomial to $0$ . The discriminant of this polynomial is $(5^{2} - 4 \times 1 \times 6) = 1$ .

$\begin{aligned}x_{1} &= \frac{-5 + \sqrt{1}}{2\times 1} \\ &= \frac{-5 + 1}{2} \\ &= -2\end{aligned}$ .

Similarly:

$\begin{aligned}x_{2} &= \frac{-5 - \sqrt{1}}{2\times 1} \\ &= \frac{-5 - 1}{2} \\ &= -3\end{aligned}$ .

By the Factor Theorem, if $x = x_{0}$ is a root of a polynomial, then $(x - x_0)$ would be a factor of that polynomial. Note the minus sign between $x$ and $x_{0}$ .

The root $x = -2$ corresponds to the factor $(x - (-2))$ , which simplifies to $(x + 2)$ .
The root $x = -3$ corresponds to the factor $(x - (-3))$ , which simplifies to $(x + 3)$ .

Verify that $(x + 2)\, (x + 3)$ indeed expands to the original polynomial:

$\begin{aligned}& (x + 2)\, (x + 3) \\ =\; & x^{2} + 2\, x + 3\, x + 6 \\ =\; & x^{2} + 5\, x + 6\end{aligned}$ .

4 0

2 years ago