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3 years ago

What are the possible rational zeros of f(x) = x4 + 6x3 − 3x2 + 17x − 15? (2 points)

1 answer:

8 0

Solve for x. The multiplicity of a root is the number of times the root appears.

x= -6.847415 (multiplicity of 1)
x= 0.793705 (multiplicity of 1)

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X·|2x+5|+2x·|x-3|=35

VARVARA [1.3K]

You have the answer into the images.

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3 years ago

A light bulb consumes 3600 watt-hours per day. How many watt-hours does it consume in 5 days and 6 hours?

Cerrena [4.2K]

Answer:

18900 watt-hours

Step-by-step explanation:

3600 x 24 (hours in a day) = 150

150 x 6 (hours) = 900

3600 (watt hours per day) x 5 (days) = 18000

18000 x 900 = 18900

total= 18900

8 0

2 years ago

Find the product. (n + 8)(n - 2)

Margaret [11]

If you would like to find the product (n + 8) * (n - 2), you can do this using the following steps:

(n + 8) * (n - 2) = n * n - 2 * n + 8 * n - 8 * 2 = n^2 + 6 * n - 16

The correct result would be n^2 + 6 * n - 16.

7 0

3 years ago

Read 2 more answers

What is the answer to 10 - 3/4?

3241004551 [841]

We'll find out what three fourths of 10 is and turn it into a negative

Hope this helps

4 0

3 years ago

Read 2 more answers

In Pennsylvania the average IQ score is 101.5 The variable is normally distributed and the population standard deviation is know

elena-14-01-66 [18.8K]

Answer:

P-value = 0.0368

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 101.5

Sample mean, $\bar{x}$ = 106.4

Sample size, n = 30

Alpha, α = 0.05

Population standard deviation, σ = 15

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 101.5\\H_A: \mu> 101.5$

We use One-tailed(right) z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{106.4 - 101.5}{\frac{15}{\sqrt{30}} } = 1.789$

Now, $z_{critical} \text{ at 0.05 level of significance } = 1.64$

Since,

$z_{stat} > z_{critical}$

We reject the null hypothesis and accept the alternate hypothesis. Thus, students in Pennsylvania have an IQ that is significantly greater than the state average.

P-value can be calculated with the standard normal table.

P-value = 0.0368

P-value is lower than the significance level.

4 0

3 years ago