All categories

3 years ago

Hrgrgrgrhheyeyehryryryryrhryryhrhrhrhrududdyryrydy

Mathematics

1 answer:

Mazyrski [523]3 years ago

5 0

Answer True

Step-by-step explanation:

It is true because you are crazy.

You might be interested in

Blake is cutting a piece of rope into fourths if each piece is 16 inches long what is the length of the entire rope

Dovator [93]

The length of the entire rope is 64 inches as when it is cut into four pieces one is 16 therefore when multiplying 16 by four you should get the length of the entire rope which is 64.

8 0

2 years ago

Running times for 400 meters are Normally distributed for young men between 18 and 30 years of age with a mean of 93 seconds and

kkurt [141]

Answer: The running time should at least 119.32 seconds to be in the top 5% of runners.

Step-by-step explanation:

Let X= random variable that represents the running time of men between 18 and 30 years of age.

As per given, X is normally distrusted with mean $\mu=93\text{ seconds}$ and standard deviation $\sigma=16\text{ seconds}$ .

To find: x in top 5% i.e. we need to find x such that P(X<x)=95% or 0.95.

i.e. $P(\dfrac{X-\mu}{\sigma}$

$P(Z$

Since, z-value for 0.95 p-value ( one-tailed) =1.645

So,

Hence, the running time should at least 119.32 seconds to be in the top 5% of runners.

6 0

2 years ago

How will the size of the model for 100,000 compare to the size of the model for 10,000

timama [110]

The 100,000 size is 10x the size of the 10,000 <span>model</span>.

6 0

2 years ago

Need help please!!!!!!!!!!!!!!!!!!!!!!!!!!

Valentin [98]

Answer:

The correct answer is -2/9

Step-by-step explanation:

You can solve this by simply multiplying 5/6 and -4/15:

$\frac{5}{6} * \frac{-4}{15}\\= \frac{-20}{90}\\= \frac{-2}{9}$

7 0

2 years ago

Lake Mead contains approximately 28,945,000 acre feet of water and there are about 326,099 gallons in 1 acre-foot. The approxima

kherson [118]

Answer:

Step-by-step explanation:

Let x be the number of gallons of water in lake Mead.

Given that there is 326099 gallons in 1 acre-foot, we calculate Mead's gallons as:

$1 acrefoot=326099g\\28945000acrefoot=x\\\\x=\frac{28945000acrefoot\times326099g}{1acrefoot}\\\\x=9.4\times 10^{12} \ gallons$

We now equate x to $9.4\times10^a$ ;

$9.4\times 10^a=9.4\times 10^{12}\\\\a=12$

Hence, a=12

6 0

2 years ago