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kvasek [131]
3 years ago
10

Can someone please help me on this one!!!!

Mathematics
1 answer:
VashaNatasha [74]3 years ago
5 0
This appears to be about rules of exponents as much as anything. The applicable "definitions, identities, and properties" are
  i^0 = 1 . . . . . as is true for any non-zero value to the zero power
  i^1 = i . . . . . . as is true for any value to the first power
  i^2 = -1 . . . . . from the definition of i
  i^3 = -i . . . . . = (i^2)·(i^1) = -1·i = -i
  i^n = i^(n mod 4) . . . . . where "n mod 4" is the remainder after division by 4


1. = -3^4·i^(3·2+0+2·4) = -81·i^14 = 81

2. = i^((3-5)·2+0 = i^-4 = 1

3. = -2^2·i^(4+2+2+(-1+1+5)·3+0) = -4·i^23 = 4i

4. = i^(3+(2+3+4+0+2+5)·2) = i^35 = -i

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You are working on an experiment where you want to test the effects of caffeinated beverages on the behavior of cats. You will t
vichka [17]
For the experiment, you need 2L of cola. Your first option would be to purchase 1 2L bottle of cola for $2.25. 

To calculate the second option, let's convert milliliters to liters first. There are 1,000 milliliters in 1 liter. With this, we know that there are 2,000 milliliters in 2 liters. Option 2 comes in 500-milliliter cans, which means that you would need 4 of them (2,000/500 = 4). 4 cans multiplied by $0.50 would cost you $2.00. 

Let's check the cost of your answer options.
A. 4 cans - As seen above, this would cost $2.00.
B. 1 bottle - From the question, we know this would cost $2.25.
C. 2 bottles - This would be more soda than you need and would cost $4.50 ($2.25x2)
D. 1 can - This would be .5L and not enough soda for the experiment.
E. 5 cans - This would cost $2.50, but would be an extra 500mL of soda.
F. 2 cans - This would only be 1L of soda and not enough for the experiment.
G. 3 cans - This would be 1.5L of soda and not enough for the experiment either.

For the best price option, you would choose A (four cans of soda). This would give you the amount of soda that you need at the lowest price.
6 0
3 years ago
(3.)FACTOR: 55d + 10?
Alexandra [31]
55d+10
55/11=5.
10/5=2
5(11)+2
4 0
3 years ago
If CB =3(x+8) and AD= 4(x+3), find AB
kkurt [141]

CD=CA+AB+BD

AB=CD-CA-BD

AB=CD-BD-BD

AB=CD-2.BD

AB=CD-2(BC+CD)

AB=CD-2BC-2CD

AB=-(CD+2BC)

AB=-{98-6(x+8)}

AB= 6x-50

6 0
3 years ago
A point is randomly chosen on a map of North America. Describe the probability of the point being in each location: North Americ
Aleks04 [339]

Answer:

We know that the map is of North America:

The probabilities are:

1) North America:

As the map is a map of North America, you can point at any part of the map and you will be pointing at North America, so the probability is p = 1

or 100% in percentage form.

2) New York City.

Here we can think this as:

The map of North America is an extension of area, and New Yorck City has a given area.

As larger is the area of the city, more probable to being randomly choosen, so to find the exact probability we need to find the quotient between the area of New York City and the total area of North America:

New York City = 730km^2

North America = 24,709,000 km^2

So the probability of randomly pointing at New York City is:

P = ( 730km^2)/(24,709,000 km^2) = 3x10^-5 or 0.003%

3) Europe:

As this is a map of Noth America, you can not randomly point at Europe in it (Europe is other continent).

So the probaility is 0 or 0%.

5 0
3 years ago
Find the average of the following numbers −30 and 25
alina1380 [7]

Answer: -2.5

Step-by-step explanation:

The average can be found by adding up the numbers then dividing by how many numbers there are in this case there are two numbers.

-30+25=-5

-5/2 = -2.5

7 0
3 years ago
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