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g100num [7]
3 years ago
14

The graph represents the piecewise function

Mathematics
2 answers:
tester [92]3 years ago
6 0
<h2>Answer:</h2>

Hence, we have:

        f(x)= 2x-1   when  x ≤ -1

                x+4    when  x ≥ 1

<h2>Step-by-step explanation:</h2>
  • After looking at the graph we observe that in the region:  x ≤ -1

The graph is a straight line that passes through (-1,-3) and (-2,-5)

Hence, the equation of line is:

f(x)-(-3)=\dfrac{-5-(-3)}{-2-(-1)}\times (x-(-1))\\\\\\f(x)+3=\dfrac{-5+3}{-2+1}\times (x+1)\\\\\\f(x)+3=2(x+1)\\\\\\f(x)=2x+2-3\\\\\\f(x)=2x-1

  • Also, in the interval  x ≥ 1

The graph is a straight line that passes through (1,5) and (2,6)

Hence, the equation of line is:

 f(x)-5=\dfrac{6-5}{2-1}\times (x-1)\\\\\\f(x)-5=x-1\\\\\\f(x)=x-1+5\\\\\\f(x)=x+4

svlad2 [7]3 years ago
3 0
Left equatoin seems to be x is less than or equal to -1
the slope seems to be 2 and y intercep tis -1 so 2x-1


right equation is x is greater than or equal to 1
slope is 1 and y intercept is 4 so x+4




top left blank is x+4, top right blank is x is greater than or equal to 1
bottom left blank is 2x-1, bottom right blank is x is less than or equal to -1
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If an object is projected upward into the air from ground level, then the height h(t) of the object
AfilCa [17]

Answer:

21.5secs

Step-by-step explanation:

Given the function that models the height of an object as

h(t) = -16t^2+ 344t

The object hit the ground at h(t) = 0

Substitute

0 =  -16t^2+ 344t

16t^2 = 344t

16t = 344

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t =  21.5

Hence it takes 21.5secs for the object to hit the ground

5 0
3 years ago
The 16th term of an AP is three times the 5th term.If the 12th term is 20 more the 7th term.Find the first term and the common d
Vlad1618 [11]
<h3><u>Answer:</u></h3>

  • First term = 6
  • Common difference= 4

<h3><u>Solution</u><u>:</u></h3>

Let's take the first term as <u>a</u> and the common difference be <u>d</u>

The formula to find the nth term of an arithmetic progression is given by :

  • an = a + ( n - 1 ) d

<u>According to question, we have :</u>

  • 16th term of an AP is three times the 5th term.

➝ a16 = 3 ( a5 )

➝ a + ( 16 - 1 )d = 3 ( a + ( 5 - 1 )d )

➝ a + 15d = 3 ( a + 4d )

➝ a + 15d = 3a + 12d

➝ 15d - 12d = 3a - a

➝ 3d = 2a

➝ 2a = 3d

➝ <u>a = 3d/2</u><u>‎</u>ㅤ‎ㅤ‎ㅤ⸻ ( 1 )

  • And, the 12th term is 20 more the 7th term.

➝ a12 - ( a7 ) = 20

➝ a + ( n - 1 )d -( a + ( n - 1 )d ) = 20

➝ a + ( 12 - 1 )d - + a + ( 7 - 1 )d ) = 20

➝ a + 11d - ( a + 6d ) = 20

➝ a - a + 11d - 6d = 20

➝ 5d = 20

➝ d = 20/ 5

➝<u> d = 4</u>

  • <u>Using</u><u> equation</u><u> (</u><u> </u><u>1</u><u> </u><u>)</u>

➝ a = 3d / 2

➝ a = ( 3 × 4 ) / 2

➝ a = 12 / 2

➝<u> a = 6</u>

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