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3 years ago

15

write a mixed number in simplest form to represent the number of pounds equivalent to each number of ounces . 66 oz = blank lb

1 answer:

sergiy2304 [10]3 years ago

5 0

The answer would probably be 4 1/8 lb

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Find the product of all real values of r for which 1/2x=r-x/7

Dahasolnce [82]

Answer:

$r = \±\sqrt{14$

$Product = -14$

Step-by-step explanation:

Given

$\frac{1}{2x} = \frac{r - x}{7}$

Required

Find all product of real values that satisfy the equation

$\frac{1}{2x} = \frac{r - x}{7}$

Cross multiply:

$2x(r - x) = 7 * 1$

$2xr - 2x^2 = 7$

Subtract 7 from both sides

$2xr - 2x^2 -7= 7 -7$

$2xr - 2x^2 -7= 0$

Reorder

$- 2x^2+ 2xr -7= 0$

Multiply through by -1

$2x^2 - 2xr +7= 0$

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

$b^2 - 4ac = 0$

For a quadratic equation

$ax^2 + bx + c = 0$

By comparison with $2x^2 - 2xr +7= 0$

$a = 2$

$b = -2r$

$c =7$

Substitute these values in $b^2 - 4ac = 0$

$(-2r)^2 - 4 * 2 * 7 = 0$

$4r^2 - 56 = 0$

Add 56 to both sides

$4r^2 - 56 + 56= 0 + 56$

$4r^2 = 56$

Divide through by 4

$r^2 = 14$

Take square roots

$\sqrt{r^2} = \±\sqrt{14$

$r = \±\sqrt{14$

Hence, the possible values of r are:

$\sqrt{14$ or $-\sqrt{14$

and the product is:

$Product = \sqrt{14} * -\sqrt{14}$

$Product = -14$

8 0

3 years ago

If x2 =<br> 20, what is the value of x?

leva [86]

Answer:

the square root of 20 is 4.472135955

Step-by-step explanation:

4 0

3 years ago

There are 336 students attending summer

ra1l [238]

Answer:

126 are boys

Step-by-step explanation:

6 0

3 years ago

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If a person walks 1/3 mile in 1/5 minutes, how far will that person walk in one hour?

astra-53 [7]

1/15 miles because you’re basically multiplying the fractions i believe

7 0

2 years ago

Read 2 more answers

What is the solution of log4(2x-6)=2

Flauer [41]

Answer: $x=11$

Step-by-step explanation:

Remembert that, by definition:

$log_b(x)=y$ → $b^y=x$

Then, you can rewrite $log_4(2x-6)=2$ in exponential form:

$4^2=2x-6$

Now you can solve for the variable "x":

Add 6 to both sides of the equation:

$4^2+6=2x-6+6$

$22=2x$

And finally you must divide both sides of the equation by 2, then:

$\frac{22}{2}=\frac{2x}{2}\\\\x=11$

3 0

3 years ago