Answer:
1680 ways
Step-by-step explanation:
Total number of integers = 10
Number of integers to be selected = 6
Second smallest integer must be 3. This means the smallest integer can be either 1 or 2. So, there are 2 ways to select the smallest integer and only 1 way to select the second smallest integer.
<u>2 ways</u> <u>1 way</u> <u> </u> <u> </u> <u> </u> <u> </u>
Each of the line represent the digit in the integer.
After selecting the two digits, we have 4 places which can be filled by 7 integers. Number of ways to select 4 digits from 7 will be 7P4 = 840
Therefore, the total number of ways to form 6 distinct integers according to the given criteria will be = 1 x 2 x 840 = 1680 ways
Therefore, there are 1680 ways to pick six distinct integers.
Answer:
I think -7; +1
(sorry if I write this but the answer must be at least 20 characters long)
<u>Answer:</u> 5 years!
<u>Reasoning:</u>
Year 1: 2700 x .70=1890
Year 2: 1890 x .70= 1323
Year 3: 1323 x .70= 926.1
Year 4: 926.1 x .70= 648.27
Year 5: 648.27 x .70=453.79
The answer is less than.....too sure
8.01 Is the answer your welcome