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Anettt [7]
3 years ago
8

Jillian flew to New Zealand for summer vacation. While she was there, she rode her bike 1/3 of the time. She spent 1/4 of the re

maining time traveling by train, and the rest of the time she stayed at a beach house. If she rode her bike for 24 hours, how many days did she ride the train? (PLEASE SHOW STEPS!)
Mathematics
1 answer:
Elis [28]3 years ago
7 0
If the time she rode her bike is 24, then 24*3 would be the Whole time she was there. She was there for a total of 72 hours.
Subtract 24 from 72 because it's 1/3 and you need the other time.
You get 48.
You need to find 1/4 of 48, so you divide it by 4.
48/4 = 12.
She rides the train for 12 hours. This is 1/2 of a day, so your answer is:

She rides the train for 1/2 of a day.
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Answer: B. y-1=2(x-3)

Step-by-step explanation:

First subtract both sides by 2x so it becomes -y=-2x-1

Second divide both sides by -1 so it becomes y=2x+1

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What's the flux of the vector field F(x,y,z) = (e^-y) i - (y) j + (x sinz) k across σ with outward orientation where σ is the po
emmasim [6.3K]
\displaystyle\iint_\sigma\mathbf F\cdot\mathrm dS
\displaystyle\iint_\sigma\mathbf F\cdot\mathbf n\,\mathrm dS
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\displaystyle\iint_\sigma\mathbf F\cdot(\mathbf r_u\times\mathbf r_v)\,\mathrm dA

Since you want to find flux in the outward direction, you need to make sure that the normal vector points that way. You have

\mathbf r_u=\dfrac\partial{\partial u}[2\cos v\,\mathbf i+\sin v\,\mathbf j+u\,\mathbf k]=\mathbf k
\mathbf r_v=\dfrac\partial{\partial v}[2\cos v\,\mathbf i+\sin v\,\mathbf j+u\,\mathbf k]=-2\sin v\,\mathbf i+\cos v\,\mathbf j

The cross product is

\mathbf r_u\times\mathbf r_v=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\0&0&1\\-2\sin v&\cos v&0\end{vmatrix}=-\cos v\,\mathbf i-2\sin v\,\mathbf j

So, the flux is given by

\displaystyle\iint_\sigma(e^{-\sin v}\,\mathbf i-\sin v\,\mathbf j+2\cos v\sin u\,\mathbf k)\cdot(\cos v\,\mathbf i+2\sin v\,\mathbf j)\,\mathrm dA
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\displaystyle5\int_0^{2\pi}(1-\cos2v)\,\mathrm dv=5\left(v-\dfrac12\sin2v\right)\bigg|_{v=0}^{v=2\pi}=10\pi
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vladimir1956 [14]
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Kobotan [32]

Answer:

<h2>(1 + 3i)(1 – 3i) gives real number product</h2>

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Given the expressions

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Performing operations on

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Performing operations on

(1 + 3i)(1 - 3i) \\= 1-3i+3i-9(i)^2 \\= 1+0-9(-1) \\= 1+9=10

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Katyanochek1 [597]

1+1+1+1+1+1+1+1+3+9

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Must click thanks and mark brainliest

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