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Alex_Xolod [135]
3 years ago
6

A combination lock has 6 different numbers. If each number can only be used ONCE, how many different combinations are possible?

Mathematics
1 answer:
Aloiza [94]3 years ago
5 0

Answer:

151200 ways

Step-by-step explanation:

Well assuming the numbers go from 0 to 9

we have

_ _ _ _ _ _ six spaces

in the first one can go one of the ten so the first one has 10 options

10*_ _ _ _ _

the second one has 9 options because we have used one alredy

and so on

10*9*8*7*6*5=151200

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Given a bag of 5 blue, 3 green, and 8 red marbles.. What is the probability of picking a blue
Anvisha [2.4K]

b = 5, \: g = 3, \: r = 8

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p(b) =  \frac{5}{16}

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6 0
2 years ago
When we slice a three-dimensional object, we expose new faces that are two dimensional. The two-dimensional face is called _____
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Answer:

Cross section

Step-by-step explanation:

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8 0
3 years ago
Figure TUVW ≅ figure ABCD, AB = 12, CD = 6, and DA = 4.
Olegator [25]
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6 0
3 years ago
Read 2 more answers
The area of trapezoid TRAP is 100 m squared
Anastasy [175]
Answer:  30 m ; (or, write as: "30 meters") .
______________________________________________
Explanation:
____________________

Area of a trapezoid, "A" = (1/2) ( b₁ + b₂) h ;
______________________________________________
or, write as:  A = ( b₁ + b₂) h  / 2 ;
___________________________________
in which:  A = area;
              b₁ = length of "base 1" (choose either one of the 2 (two bases);
              b₂ = length of "base 2" (use the base that is remaining);
              h = height of trapezoid;
____________________________________________
From the information given: 
___________________________
A = 100 m² ; 
h = 5 m
b₁ = 10 m
b₂ =  x 
___________________________
Find "x", which is:  "b₂" ;
__________________________
      A = ( b₁ + b₂) h  / 2  ;
_____________________________
Plug in our known values; and plug in "x" for "b₂" ; and solve for "x" ;
_________________________________________________________
  100 m² = [(10m + x) (5m)] / 2  ; Solve for "x" ;
_________________________________________________________
          (10m + x) (5m) = (2)* (100m²) ;
_________________________________________________________
             (5m) (10m + x) = 200 m² ;
___________________________________________
Note:  The distributive property of multiplication:
____________________________________________
    a(b+c) = ab + ac ;
 
    a(b−c) = ab <span>− ac ;
</span>____________________________________________

  We have:  (5m) (10m + x) = 200 m²  ;
____________________________________________
So:    (5m) (10m + x) =  (5m*10m) + (5m * x) ;
                           
                               =  50m² + (5m)x  ;
_______________________________________________
     →  50m² + (5m)x = 200m²  ; 
_______________________________________________
Divide the ENTIRE equation by "5m" ;
_______________________________________________
     → { 50m² + (5m)x } / 5m = (200m² / 5m) ;
_______________________________________________
     →  10m + x   = 40m ; 
________________________________________________
Now, subtract "10m" from EACH side of the equation; to isolate "x" on one side of the equation; and to solve for "x" ;
_______________________________________
     →  10m + x  − 10m  =  40m − 10m ;

to get:

                →    x  =  30 m  ; which is our answer.
___________________________________________________
Answer:  30 m ; (or, write as: "30 meters") .
_____________________________________________________
6 0
3 years ago
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