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Alex_Xolod [135]
3 years ago
6

A combination lock has 6 different numbers. If each number can only be used ONCE, how many different combinations are possible?

Mathematics
1 answer:
Aloiza [94]3 years ago
5 0

Answer:

151200 ways

Step-by-step explanation:

Well assuming the numbers go from 0 to 9

we have

_ _ _ _ _ _ six spaces

in the first one can go one of the ten so the first one has 10 options

10*_ _ _ _ _

the second one has 9 options because we have used one alredy

and so on

10*9*8*7*6*5=151200

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vivado [14]
  • Answer:

<em>x₁ = 3</em>

<em>x₂ = - 12</em>

  • Step-by-step explanation:

<em>Hi there ! </em>

<em>| 2x + 9 | = 15</em>

<em>1.</em>

<em>2x + 9 = 15</em>

<em>2x = 15 - 9</em>

<em>2x = 6</em>

<em>x = 6 : 2</em>

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<em>2.</em>

<em>2x + 9 = - 15</em>

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<em>x = - 24 : 2</em>

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<em>Good luck ! </em>

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Step-by-step explanation:

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