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konstantin123 [22]
3 years ago
8

Can someone please explain and answer. There is only 1 question. There is a picture. Thank you

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
6 0
Try using the web. it's very helpful. use cymath.com
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The tables below show two functions. For each set of data:
slamgirl [31]
The first table, representing <em>f</em>(<em>x</em>), is linear.  The data have a constant rate of change or slope:
<em />(between the first two points):  <em>m</em> = (<em>y</em>₂ - <em /><em>y</em>₁)/(<em>x</em>₂ - <em>x</em>₁) = (22-18)/(-1--2) = 4/(-1+2) = 4/1 = 4.  The rate of change  between any two points is the same:
(between the last two points):<em>  m</em> = (34-30)/(2-1) = 4/1 = 4.

The second table, representing <em>g</em>(<em>x</em>), is exponential.  The data points are multiplied by the same constant between successive points.  2*2 = 4; 4*2= 8; 8*2 = 16, etc.
4 0
2 years ago
Between which two numbers on the number line is B?
Vanyuwa [196]

Answer:

C. Between 4 and 5.......

6 0
2 years ago
Read 2 more answers
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

The above equation can be better expressed as:

y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

p(x) = \dfrac{(x+2)}{(x^2-4)^2} \

p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \

p(x) = \dfrac{1}{(x+2)(x-2)^2}

Also;

q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{1}{(x-2)^2}

\implies \dfrac{1}{16}

\lim \limits_{x \to-2} (x+ 2)^2 q(x) =  \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{7}{(x-2)^2}

\implies \dfrac{7}{16}

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0
3 years ago
1. What is the solution of the equation<br> 3y-5y+10=36?<br> 1. -13<br> 2. 2<br> 3. 4.5<br> 4. 13
VikaD [51]

Answer:

1: -13

Step-by-step explanation:

First, simplify the equation to -2y+10=36

Subtract 10 from both sides

-2y=26

Divide negative 2 from both sides

y=-13

5 0
2 years ago
Read 2 more answers
Please answer will mark as brainist!
Elena L [17]

Answer:

A. Y = 2/3x

Step-by-step explanation:

Each Y is 1/3 less than X

7 0
2 years ago
Read 2 more answers
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