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dexar [7]
3 years ago
15

When throwing fair dice, all six faces of each die are equally likely. there are thirty-six total possible outcomes (any of the

six faces of die a can be matched with any of the six faces of die b). what is the probability the sum of the pips (spots) on the two faces is at least 9?

Mathematics
1 answer:
Marysya12 [62]3 years ago
6 0

Answer:

Probability of sum of pips on two faces is at least 9 = \frac{5}{18}

Step-by-step explanation:

Experiment:  Throwing two fair dice.

Total no of Outcome = 6^2 = 36

Sample space (list of outcome) is attached.

Let E be the event that sum of pips on two faces is at least 9.

Probability \:(\,Event \:E\,)\: =\;\frac{No.\: of\: favorable\: outcome\:of\: Event\: E}{Total\: No.\: of \:Outcome}

Favorable outcome are where sum is 9 , 10 , 11 and 12.

From Sample space, No. of Favorable outcome = 10

∴ Prob\: (\: E\: ) = \frac{10}{36}

Prob\: (\: E\: ) = \frac{5}{18}

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Solution: The factor form of the given polynomial is f(x)=(x+4)(x+3)(x+2)(x+1).

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Similarly (x+2) is the factor of given polynomial because for x=-2 the value of parenthesis polynomial is 0.

Use synthetic method to divide the parenthesis polynomial for by (x+2). it is shown in figure 2.

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4 0
3 years ago
What is the area of this parallelogram?<br><br> 44 cm²<br><br> 55 cm²<br><br> 99 cm²<br><br> 220 cm²
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Here, we can split this parallelogram into two triangles and one rectangle. The triangles are equal to each other so we can just find the area of the rectangle and the are of <span>one triangle. 

</span>Triangle area formula: a= \frac{1}{2} bh, where a = area, b=base, and h=height.

Plug in 5 for b and 11 for h:

\frac{1}{2}*11*5 =  \frac{55}{2}
<span>Multiply by 2!
</span>\frac{55}{2} *2=55

Rectangle area formula: a=bh, where a = area, b = base, and h = height.

Plug in 4 for b and 11 for h.

a = 4 x 11
a = 44

44+55 = 99

Area is 99 cm<span>².</span>
7 0
3 years ago
Read 2 more answers
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