When throwing fair dice, all six faces of each die are equally likely. there are thirty-six total possible outcomes (any of the
six faces of die a can be matched with any of the six faces of die b). what is the probability the sum of the pips (spots) on the two faces is at least 9?
1 answer:
Answer:
Probability of sum of pips on two faces is at least 9 =
Step-by-step explanation:
Experiment: Throwing two fair dice.
Total no of Outcome = = 36
Sample space (list of outcome) is attached.
Let E be the event that sum of pips on two faces is at least 9.
Favorable outcome are where sum is 9 , 10 , 11 and 12.
From Sample space, No. of Favorable outcome = 10
∴
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Answer:
0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.
The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.
Step-by-step explanation:
Assume that the probability of a defective computer component is 0.02. Components are randomly selected. Find the probability that the first defect is caused by the seventh component tested.
First six not defective, each with 0.98 probability.
7th defective, with 0.02 probability. So
0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.
Find the expected number and variance of the number of components tested before a defective component is found.
Inverse binomial distribution, with
Expected number before 1 defective(n = 1). So
Variance is:
The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.