Completed question:
In the game of tic-tac-toe, if all moves are performed randomly the probability that the game will end in a draw is 0.127. Suppose six random games of tic-tac-toe are played. What is the probability that at least one of them will end in a draw?
Answer:
0.557
Step-by-step explanation:
For each game, the probability of not end in a draw is 1 - 0.127 = 0.873. Thus, because each game is independent of each other, the probability of all of them not end in a draw is the multiplication of the probability of each one:
0.873x0.873x0.873x...x0.873 = 0.873⁶ = 0.443
Thus, the probability that at least one of them end in a draw is the total probability (1) less the probability that none of them en in a draw:
1 - 0.443
0.557
Answer:
100-both
75-5
565- 5
2815- 5
10050- both
57- 3
1365- 3
14- 2
81- 3
3850- 2
333- 9
1125- 9
448- 8
630- 9
5496- 8
114- 6
21,750- 6
3580- 4
2528- 4
944- 4
Step-by-step explanation:
Answer:
She subtracted 7x instead of dividing it. Personally, i wouldn't have done that. I would subtract the 14 first, then divide.
Answer:
x=3.5
Step-by-step explanation:
Answer:
A. can cause disease
Step-by-step explanation: