Question

What is an equation for the linear function whose graph contains the points (−1, −2) and (3, 10) ? Enter your answers in the boxes. y+ = (x+1)

Answer 1

$\bf \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~{{ -1}} &,&{{ -2}}~) % (c,d) &&(~{{ 3}} &,&{{ 10}}~) \end{array} \\\\\\ % slope = m slope = {{ m}}\implies \cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{10-(-2)}{3-(-1)}\implies \cfrac{10+2}{3+1} \\\\\\ \cfrac{12}{4}\implies \cfrac{3}{1}\implies 3$

$\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-2)=3[x-(-1)] \\\\\\ y+2=3(x+1) \implies y+2=3x+3\implies y=3x+1$

Answer 2

Answer: y+2=3(x+1)

the 1st box you would put 2 and then the 2nd box you would put 3

hope this helps i took the test and got it right

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