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3 years ago

[736200-53896:2-(240424+76):100+238009]:36=

Mathematics

1 answer:

KatRina [158]3 years ago

7 0

How about go look in the calculator?

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How to solve this??<br><br> (r^-7b^-8) ^0<br> -------------<br> (t^-4w)

professor190 [17]

keeping in mind that anything raised at the 0 power, is 1, with the sole exception of 0 itself.

$\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad a^n\implies \cfrac{1}{a^{-n}}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\cfrac{(r^{-7}b^{-8})^0}{t^{-4}w}\implies \cfrac{1}{t^{-4}w}\implies \cfrac{1}{t^{-4}}\cdot \cfrac{1}{w}\implies t^4\cdot \cfrac{1}{w}\implies \cfrac{t^4}{w}$

6 0

3 years ago

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Whats the answer to this?

sweet-ann [11.9K]

Answer:

153 cm^2

Step-by-step explanation:

The area is given by

A = b*h

= 17*9

=153 cm^2

8 0

3 years ago

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Difference between complementary and Supplementary

jonny [76]

Complementary angles sum to 90°. Supplementary angles sum to 180°.

3 0

2 years ago

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You plan to put anti-theft devices on each garment in your store. You have 1,320 garments, and it takes an employee 20 seconds t

makvit [3.9K]

Answer:

3 hours 40 minutes.

Step-by-step explanation:

We are told that we have 1320 garments and it takes an employee 20 seconds to tag a garment.

1 employee tags one garment in 20 seconds.

So garments tagged by 1 employees in 1 minute will be $\frac{60}{20} =3$ garments.

2 employees will tag 3*2=6 garments in 1 minute.

To find the total time it will take two employees to tag all the garments we will divide total number of garments by 6.

$\text{Time taken by two employees to tag 1320 garments}=\frac{1320}{6}$

$\text{Time taken by two employees to tag 1320 garments}=220$

Therefore, it will take 220 minutes or 3 hours and 40 minutes for 2 employees to tag 1320 garments.

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4 years ago

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Determine whether each of these functions is O(x^2 ).

otez555 [7]

Answer:

(a) no
(b) yes
(c) no
(d) no

Step-by-step explanation:

"Of the order x^2" means the dominant behavior matches that of x^2 as x gets large. For polynomial functions, the dominant behavior is that of the highest-degree term.

For other functions, the dominant behavior will typically be governed in some other way. Here, the rate of growth of the x·log(x) function is determined by log(x), which has decreasing slope as x increases.

Only answer selection B has a highest-degree term of x^2, so only that one exhibits O(x^2) behavior.

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3 years ago

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