Answer:
m<1 = 39
m<2 = 51
Step-by-step explanation:
For this problem, you need to understand that a little square in the bottom of two connecting lines represents a right-angle (an angle this 90 degrees). This problem, gives you two relationships for angle 1 and angle 2 within a right-angle. Using this information, we can solve for the measures of the two angles.
Let's write the two relations:
m< 1 = 3x
m< 2 = x + 38
And now let's right an equation that represents the two angles to the picture:
m<1 + m<2 = 90
Using this information, let's substitute the expressions we have for the two angles and solve for x. Once we have the value of x, we can find the measure of the two angles.
m< 1 + m< 2 = 90
(3x) + (x + 38) = 90
3x + x + 38 = 90
x ( 3 + 1 ) + 38 = 90
x ( 4 ) + 38 = 90
4x + 38 = 90
4x + 38 - 38 = 90 - 38
4x = 90 - 38
4x = 52
4x * (1/4) = 52 * (1/4)
x = 52 * (1/4)
x = 13
Now that we have the value of x, we simply plug it back into our expressions for the m<1 and m<2.
m<1 = 3x = 3(13) = 39
m<2 = x + 38 = 13 + 38 = 51
And we can verify this is correct with the relational equation:
m<1 + m<2 = 90
39 + 51 ?= 90
90 == 90
Hence, we have found the values of m<1 and m<2.
Cheers.
The given sequence is not arithmetic sequence
<em><u>Solution:</u></em>
Given sequence is:

We have to find if the above sequence is arithmetic sequence or not
An arithmetic sequence is a sequence of numbers such that the difference of any two successive members of the sequence is a constant
<em><u>Here in the given sequence</u></em>

<em><u>Let us find the difference between terms</u></em>




Thus the difference between terms is not constant
So the given sequence is not arithmetic sequence
Amount earned in compound interest = P(1 + r)^n; where P is the principal, r is the rate and n is the number of periods.
Amount = 3,000(1 + 14%)^6 = 3,000(1 + 0.14)^6 = 3,000(1.14)^6 = $6,584.91
No, the trailer cannot hold the weight of the bricks. It is beyond the 900kg capacity of the trailer. The total weight of the bricks is 1,013.77 kilograms. The total weight was derived from getting the volume of the brick (0.051m x 0.102m x 0.203m), then multiplying the volume to the density of each brick (1.056 x 10^3m^3 x 1920kg/m^3). The weight of each brick is 2.03kg. Lastly, multiply the total number of bricks to the weight of each brick to get the total weight.