The pressure of 28 inches of mercury occurs about 6 miles from the eye of the hurricane. We get this from the given algebraic expression.
<h3>What is an expression?</h3>
An expression is formed by variables, constants, and algebraic operations. Since the operation among them is an algebraic or arithmetic operation, it is said to be an algebraic expression.
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Calculation:</h3>
It is given that the algebraic expression that relates the barometric pressure and the eye of the hurricane as
f(x) = 0.48 ln(x+2) + 27
Here x is the distance in miles from the eye of the hurricane.
f(x) is the pressure of the mercury in a barometer in inches
So, the required distance from the eye of the hurricane when the pressure of 28 inches of mercury in the meter is
(Here f(x) = 28)
f(x) = 0.48 ln(x+2) + 27
⇒ 28 = 0.48 ln(x+2) + 27
⇒ 0.48 ln(x+2) = 28 - 27
⇒ ln (x+2) = 1/0.48
⇒ ln(x+2) = 2.0833
Applying exponential base "e" on both sides, we get
(x+2) =
⇒ x + 2 = 8.0309
⇒ x = 8.0309 - 2 = 6.0309
When the result is rounded to the nearest whole number, we get x = 6 miles.
Thus, for the pressure of 28 inches of mercury, the eye of the hurricane is 6 miles far from the barometer.
Learn more about an expression here at the following link:
brainly.com/question/4541471
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Add 21 to both sides. -10+21 is 11. So x=11.
Answer:
Ok so first we subtract 11 on each side so we get a-11=4b-4c then we do-4b on each side to gets a-11-4b=-4c finally divide -4 to each side to get a-11-4b/-4=c
Step-by-step explanation:
Answer:
$4.85n = $24.52 where n = 5
If this doesnt match any of the equations, see if you can add the answer choices to your question
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