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Nana76 [90]
3 years ago
6

Insert a rational number between 3 and 3.5

Mathematics
2 answers:
lorasvet [3.4K]3 years ago
8 0

A rational number is any number that can be made into a fraction and is either repeating or stops when in decimal form.

Rational numbers between 3 and 3.5 would be 10/3 (3.33 repeating), and 13/4 (3.25).

Hope this helps!! :)

Ket [755]3 years ago
5 0

Answer:

3.1 , 3.2 , 3.3 and 3.4

Step-by-step explanation:

It could be any number in between 3-3.5.

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Find the least common multiple (LCM) of 54 and 72. A) 9 B) 27 C) 108 D) 216
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PLEASE HELP ASAP 25 PTS
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Hello from MrBillDoesMath!

Answer:

Choice B     (  (x+6)/5) )



Discussion:

y =  f(x) =  5x - 6

To solve for the inverse of f, replace "y" by "x" and "x" by "y" in the original equation. That is, solve for "y" in

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Step-by-step explanation:

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The head librarian at the Library of Congress has asked her assistant for an interval estimate of the mean number of books check
Verdich [7]

Answer:

n=(\frac{1.960(150)}{90})^2 =10.67 \approx 11

So the answer for this case would be n=11 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma =150 represent the population standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The confidence interval for this case is given by: (740, 920)

We can find the estimate for the mean and we got:

\bar X = \frac{740+920}{2} = 830

and the margin of error is given by :

ME = \frac{920-740}{2}= 90

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

And on this case we have that ME =90 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} s}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(150)}{90})^2 =10.67 \approx 11

So the answer for this case would be n=11 rounded up to the nearest integer

5 0
3 years ago
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