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3 years ago

Insert a rational number between 3 and 3.5

Mathematics

2 answers:

lorasvet [3.4K]3 years ago

8 0

A rational number is any number that can be made into a fraction and is either repeating or stops when in decimal form.

Rational numbers between 3 and 3.5 would be 10/3 (3.33 repeating), and 13/4 (3.25).

Hope this helps!! :)

Ket [755]3 years ago

5 0

Answer:

3.1 , 3.2 , 3.3 and 3.4

Step-by-step explanation:

It could be any number in between 3-3.5.

You might be interested in

Halla la tasa de variación de cada funcion en el intervalo [-4,3] e indica si es positiva , negativa o nula A) f(x)=x2-2x+4 B) f

masya89 [10]

Answer:

$A) \hspace{3}Rate\hspace{3}of\hspace{3}change=-5\hspace{3}Negative\\\\B)\hspace{3}Rate\hspace{3}of\hspace{3}change=-21\hspace{3}Negative$

Step-by-step explanation:

Given a function $f(x)$ , we called the rate of change to the number that represents the increase or decrease that the function experiences when increasing the independent variable from one value " $x_1$ " to another " $x_2$ ".

The rate of change of $f(x)$ between $x_1$ and $x_2$ can be calculated as follows:

$Rate\hspace{3}of\hspace{3}change=f(x_2)-f(x_1)$

For:

$f(x)=x^2-2x+4$

Let's find $f(x_1)$ and $f(x_2)$ , where:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=(-4)^2-2(4)+4=16-8+4=12\\f(x_2)=f(3)=(3)^2-2(3)+4=9-6+4=7$

So:

$Rate\hspace{3}of\hspace{3}change =7-12=-5\hspace{3}Negative$

And for:

$f(x)-3x+2$

Let's find $f(x_1)$ and $f(x_2)$ , where:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

So:

$Rate\hspace{3}of\hspace{3}change =-7-14=-21\hspace{3}Negative$

<em>Translation:</em>

Dada una función $f(x)$ , llamábamos tasa de variación al número que representa el aumento o disminución que experimenta la función al aumentar la variable independiente de un valor " $x_1$ " a otro " $x_2$ ".

La tasa de variación de $f(x)$ entre $x_1$ y $x_2$ , puede ser calculada de la siguiente forma:

$Tasa\hspace{3}de\hspace{3}variacion=f(x_2)-f(x_1)$

Para:

$f(x)=x^2-2x+4$

Encontremos $f(x_1)$ y $f(x_2)$ , donde:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

Entonces:

$Tasa\hspace{3}de\hspace{3}variacion =7-12=-5\hspace{3}Negativa$

Y para:

$f(x)-3x+2$

Encontremos $f(x_1)$ y $f(x_2)$ , donde:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

Entonces:

$Tasa\hspace{3}de\hspace{3}variacion=-7-14=-21\hspace{3}Negativa$

8 0

4 years ago

Write 5numbers 8digit long

Virty [35]

12345678
23456789
34567890
45678901
56789012

6 0

3 years ago

An old road was 3.95 miles long. After a renovation it was 3.81 times as long. How long was the road after the renovation?

guapka [62]

3.95 × 3.81 = 15.0485

The road was 15.0485 miles long after the renovation.

Hope this helps!

4 0

4 years ago

A(n)=-6+3(n-1). Find the 16th term in the sequence

marshall27 [118]

Answer:

16th term = 39.

Step-by-step explanation:

Plug 16 into the formula -6 + 3(n - 1):

A(16) = -6 + 3(16-1)

= - 6 + 3*15

= -6 + 45

= 39.

6 0

3 years ago

Read 2 more answers

Can somebody please help me with this question ?? :)

Eddi Din [679]

Answer:

Reason 3. Congruence of segments is reflexive

Reason 4. SSS

3 0

3 years ago