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3 years ago

Insert a rational number between 3 and 3.5

Mathematics

2 answers:

lorasvet [3.4K]3 years ago

8 0

A rational number is any number that can be made into a fraction and is either repeating or stops when in decimal form.

Rational numbers between 3 and 3.5 would be 10/3 (3.33 repeating), and 13/4 (3.25).

Hope this helps!! :)

Ket [755]3 years ago

5 0

Answer:

3.1 , 3.2 , 3.3 and 3.4

Step-by-step explanation:

It could be any number in between 3-3.5.

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You are preparing for a trip to Canada. At the time of your trip, each U.S. Dollar is worth 1.293 Canadian dollars and each Cana

madreJ [45]

Answer:

193.95 Canadian dollars

Step-by-step explanation:

Given: Each U.S. Dollar is worth 1.293 Canadian dollars and each Canadian dollar is worth 0.773 U.S. Dollar.

To find: Value of 150 U.S. dollars in terms of Canadian dollars

Value of 1 U.S. dollar = 1.293 Canadian dollars

To find 150 U.S. dollars in terms of Canadian dollars, multiply 150 by 1.293

Value of 150 U.S. dollars in terms of Canadian dollars = 150 × 1.293 = 193.95 Canadian dollars

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3 years ago

Help with this one because I do not know how to do perpendicular plz put explanation with steps worth 50!

Yuri [45]

Answer:

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line $2x-3y=12$ is $3x+2y=34$

Step-by-step explanation:

Given:

$2x-3y=12$

To Find:

Equation of line passing through ( 16, -7) and is perpendicular to the line

$2x-3y=12$

Solution:

$2x-3y=12$ ...........Given

$\therefore y=\dfrac{2}{3}\times x-4$

Comparing with,

$y=mx+c$

Where m =slope

We get

$Slope = m1 = \dfrac{2}{3}$

We know that for Perpendicular lines have product slopes = -1.

$m1\times m2=-1$

Substituting m1 we get m2 as

$\dfrac{2}{3}\times m2=-1\\\\m2=-\dfrac{3}{2}$

Therefore the slope of the required line passing through (16 , -7) will have the slope,

$m2=-\dfrac{3}{2}$

Now the equation of line in slope point form given by

$(y-y_{1})=m(x-x_{1})$

Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,

$(y-(-7))=-\dfrac{3}{2}\times (x-16)\\\\2y+14=-3x+48\\3x+2y=34......Equation\ of\ line$

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line $2x-3y=12$ is

$3x+2y=34$

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