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irakobra [83]
3 years ago
9

Charlie Carr has a sheet of brass that is 33 inches wide and cuts two pieces that are each 8

Mathematics
1 answer:
denis-greek [22]3 years ago
5 0

Answer: The width of the leftover brass is 17 inches.

Step-by-step explanation:

Hi, to answer this question, first, we have to add the width of the pieces cut.  

Mathematically speaking:

8 in +8 in = 16 in

Now, we have to subtract that result to the width of the sheet of brass.

33 in -16 in = 17 in

The width of the leftover brass is 17 inches.

Feel free to ask for more if needed or if you did not understand something.

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olganol [36]
2 consecutive odd integers : x and x + 2

x(x + 2) = 27 + 6(x + x + 2)
x^2 + 2x = 27 + 6(2x + 2)
x^2 + 2x = 27 + 12x + 12
x^2 + 2x - 12x - 12 - 27 = 0
x^2 -10x - 39 = 0
(x + 3)(x - 13) = 0

x + 3 = 0
x = -3 (extraneous solution)

x - 13 = 0
x = 13

x + 2 = 15 

so ur 2 integers are 13 and 15, with 15 being the largest
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Step-by-step explanation:

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