Question

How do you solve for b when the equation is 48/b^2 =750/b^5 ?

Answer 1

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Answer 2

First off, you're going to end up with 2 answers.

Alright so you have:

$\frac{48}{b^2} = \frac{750}{b^5}$

You'll want to multiply both sides by b²

You'll end up with:

$48 = \frac{750}{b^3}$

Multiply both sides by $b^5$

Now you should have:

$48b^5 = 750b^2$

Subtract 750b^2 from both sides.

Now:
$48b^5 - 750b^2 = 0$

Factor the left side of the equation:
$6b^2(2b-5)(4b^2+10b+25)=0$

Set both factors to 0:
$2b - 5 = 0$ $4b^2+10b+25=0$

Your Answers:
b = 0 or b = $\frac{5}{2}$