We should first find the gas mileage
that will be 535/21 equals to 25.5
The car's gas mileage is 25.5
To find how much the car can drive on 51 gallons of gas
25.5×51
Equals to 1300.5
the car can drive 1300.5 miles on 51 gallons of gas
Answer:
3960.4 bacteria
Step-by-step explanation:
The formula to solve the above question is given as:
P(t) = Po (2) ^t/k
P(t) = Population after time t = ?
Po = Initial population = 650 bacteria
t = Time in days = 7.3 days
k = doubling time = 2.8 days
P(t) = 650 × (2)^7.3/2.8
P(t) = 650 × 2^2.6071428571
P(t) = 650 × 6.0929582599
P(t) = 3960.4228689 bacteria.
Approximately = 3960.4 bacteria
Therefore, the number of bacteria the researcher will have after 7.3 days if they started with 650 bacteria is 3960.4 bacteria.
Answer:
f(x) – g(x) = x^2 - 4x + 3
Step-by-step explanation:
f(x) = 3x^2 - 4x + 5 and g(x) = 2x^2 + 2,
f(x) – g(x) = 3x^2 - 4x + 5 - ( 2x^2 + 2)
Distribute the minus sign
f(x) – g(x) = 3x^2 - 4x + 5 - 2x^2 - 2
Combine like terms
f(x) – g(x) = x^2 - 4x + 3