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3 years ago

C. Assume someone has an average balance account with a bank that costs $35 a month but earns

Mathematics

1 answer:

Elodia [21]3 years ago

8 0

Answer:

The total interest earned after subtracting the monthly $35

service fee = $975 - $35 = $940

Step-by-step explanation:

Bank fee cost per month = $35

Interest rate per month = 1%

The total amount in the account until the 15th = $100,000

The total amount in the account from the 15th to the 30th = $95,000

Interest Earned?

Interest earned for first 15 days:

= $100,000 times 1%/2

= $100,000 times 0.001/2

= $500

Interest earned from 15th to the 30th:

= $95,000 times 1%/2

= $95,000 times 0.001/2

= $475

Interest earned for first 15 days + Interest earned from 15th

to the 30th = $500 + $475 = $975

So, the total interest earned after subtracting the monthly $35

service fee = $975 - $35 = $940

Keywords: interest, interest rate

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Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

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The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
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3 years ago

Need help with this.

stepan [7]

Third one down. you can tell just by the first two coordinates

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Step-by-step explanation:

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