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ozzi
3 years ago
12

How do u do this? Help plz

Mathematics
1 answer:
aniked [119]3 years ago
6 0
P=2250e^(rt)
P/2250=e^(rt)
ln(P/2250)=ln(e^(rt))
ln(P/2250)=rt
r=ln(P/2250)/t
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Dr. Manion a mixed 9.357G of chemical A, 12.082g of chemical b,
Gnoma [55]

Amount of chemical A mixed in medicine = 9.357 g

Amount of chemical B mixed in medicine = 12.082 g

Amount of chemical C mixed in medicine = 7.502 g

We have to determine the total amount of medicine he prepared in grams.

Total amount of medicine

= 9.357 + 12.082 + 7.502

= 28.941 grams

So, he prepared 28.941 grams of medicine.

Now, we have to round each chemical to the nearest tenth.

Amount of chemical A mixed in medicine = 9.357 g

Rounding to nearest tenth = 9.4 grams

Amount of chemical B mixed in medicine = 12.082 g

Rounding to nearest tenth = 12.1 grams

Amount of chemical C mixed in medicine = 7.502 g

Rounding to nearest tenth = 7.5 grams

6 0
3 years ago
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Paraphin [41]
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8 0
3 years ago
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How do i write y = x -4 in a x and y chart/table?
IrinaK [193]
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tldr; we can treat this like a box that we put something into (x) and we get something back from it (y).

We can then take this data we get and put it in a table.  This is useful for finding patterns.

I will post a picture of what a table may look like.

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3 years ago
Help!!!!! Please!!!!!!!! Math!!!!!! Quickly!!!!!! Brainiest answer to correct answer!!!!!!!!
muminat
The answer should be 103. Because the interior angles of all triangles add up to 180 degrees, you can just add together the two known interior angles; subtract them from 180; and then find the supplement.
5 0
3 years ago
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How do you do this problem?
zhenek [66]

Answer:

A) g is increasing, and the graph of g is concave up.

Step-by-step explanation:

g'(x) = ∫₀ˣ e^(-t³) dt

Since e^(-t³) is always positive, ∫₀ˣ e^(-t³) dt is positive when x > 0.  So the function is increasing.

Find g"(x) by taking the derivative using second fundamental theorem of calculus:

g"(x) = e^(-x³)

g"(x) is always positive, so the function is always concave up.

5 0
3 years ago
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