1.06 , 0.90, 0.601, 0.109, 0.07
Answer:
see explanation
Step-by-step explanation:
the sum to n terms of an arithmetic sequence is
=
[2a + (n - 1)d ]
where d is the common difference and a is the first term
here d = 9 - 7 = 7 - 5 = 2 and a = 5, hence
=
[(2 × 5) + 2(n - 1) ]
=
(10 + 2n - 2)
=
(2n + 8)
= n² + 4n
When sum = 165, then
n² + 4n = 165 ← rearrange into standard form
n² + 4n - 165 = 0 ← in standard form
(n + 15)(n - 11) = 0 ← in factored form
equate each factor to zero and solve for n
n + 15 = 0 ⇒ n = - 15
n - 11 = 0 ⇒ n = 11
but n > 0 ⇒ n = 11
Answer:
my answer is A. you only need substitute n from 1 to 4
As per the the question we need to calculate the value of first 4 multiplied by 10.
Now in the number 4,043, the first 4 is at the thousands place. So the place value of first 4 in the digit 4,043 is 4000.
Multiplying the value of first 4 by 10 we get:

Now, the second 4 in the digit 4,043 is at the tens place. So the place value of second 4 in the digit 4,043 is 40.
We can see that two of them are not equal and the value of first 4 times ten is far greater than the value of second 4.
It can be said that two of the 4s in the digit 4,043 are at two different places, first is at thousands place and second is at tens place. So if the numbers are two places apart their place value will have difference of 100 folds.